PPT
... Newton’s First Law • Example of non-zero net forces: – Friction: Makes a moving block a slow down – Gravity: Makes a ball fall toward the earth • Example of zero net force – Car just sitting on the pavement • No velocity, no acceleration→no net force – Rocket ship in outer space • Nothing to slow i ...
... Newton’s First Law • Example of non-zero net forces: – Friction: Makes a moving block a slow down – Gravity: Makes a ball fall toward the earth • Example of zero net force – Car just sitting on the pavement • No velocity, no acceleration→no net force – Rocket ship in outer space • Nothing to slow i ...
PHYSICS UNIT 3 Motion
... Isaac Newton proposed three laws to explain the how and why of motion. First Law: ...
... Isaac Newton proposed three laws to explain the how and why of motion. First Law: ...
x - WordPress.com
... When the block is displaced from the equilibrium point and released, it is a particle under a net force and therefore has an acceleration. The force described by Hooke’s Law is the net force in Newton’s Second Law. ...
... When the block is displaced from the equilibrium point and released, it is a particle under a net force and therefore has an acceleration. The force described by Hooke’s Law is the net force in Newton’s Second Law. ...
Physics 207: Lecture 2 Notes
... Uniform circular motion involves only changes in the direction of the velocity vector and the associated acceleration must be perpendicular to any point on the trajectory (in the radial direction). Quantitatively (see text) v ...
... Uniform circular motion involves only changes in the direction of the velocity vector and the associated acceleration must be perpendicular to any point on the trajectory (in the radial direction). Quantitatively (see text) v ...
Notes for Mid
... 1) A runner’s initial speed is 5m/s and he accelerates at 5m/s2 over a distance of 7.5 meters. What is his final speed? vf2 = (5m/s)2 + 2*(5m/s2)(7.5m) = 100m2/s2 or vf = 10m/s 2) Same problem except the final speed was 10m/s. What was the initial speed? vi2 = (10m/s)2 – 2*(5m/s2)(7.5m) = 25m2/s2 or ...
... 1) A runner’s initial speed is 5m/s and he accelerates at 5m/s2 over a distance of 7.5 meters. What is his final speed? vf2 = (5m/s)2 + 2*(5m/s2)(7.5m) = 100m2/s2 or vf = 10m/s 2) Same problem except the final speed was 10m/s. What was the initial speed? vi2 = (10m/s)2 – 2*(5m/s2)(7.5m) = 25m2/s2 or ...
Word Format
... the block using a spring balance, the block will remain stationary until we reach some maximum force upon which time the block will begin to accelerate. ...
... the block using a spring balance, the block will remain stationary until we reach some maximum force upon which time the block will begin to accelerate. ...
