Lecture_1 - Department of Mathematics
... 5. A 100 kg woman stands with her legs making 45 degree angles with respect to the vertical direction. What is the compressive force in her knees ? 6. How is biomechanics important for orthopaedics ? 7. What is Pascal’s law for fluid statics ? 8. Compute the mass of the object on the side of the blo ...
... 5. A 100 kg woman stands with her legs making 45 degree angles with respect to the vertical direction. What is the compressive force in her knees ? 6. How is biomechanics important for orthopaedics ? 7. What is Pascal’s law for fluid statics ? 8. Compute the mass of the object on the side of the blo ...
L 6
... • It is the law which explains how things move • If a net force is applied to an object it will accelerate – change its velocity • It includes the law of inertia if there is no force F = 0, then accel = 0 the velocity doesn’t change no force is needed to keep an object moving with constant vel ...
... • It is the law which explains how things move • If a net force is applied to an object it will accelerate – change its velocity • It includes the law of inertia if there is no force F = 0, then accel = 0 the velocity doesn’t change no force is needed to keep an object moving with constant vel ...
hp1f2013_class05_NewtonsLawsApplications
... The radial acceleration that must act on the rider is R 2 . R The normal force is therefore N Ma MR 2 . The maximum static friction that can act on the rider is therefore f max N . Since we require M to be in vertical equilibrium, we need f max Mg . So N MR 2 Mg . g and the sma ...
... The radial acceleration that must act on the rider is R 2 . R The normal force is therefore N Ma MR 2 . The maximum static friction that can act on the rider is therefore f max N . Since we require M to be in vertical equilibrium, we need f max Mg . So N MR 2 Mg . g and the sma ...
HW #5
... knees in order to decelerate his torso on impact over a distance of 60cm. Bond’s torso’s mass is 45 kg. a. Calculate Bond’s velocity just before impact. b. Find the average acceleration [added later: and the average force on the torso due to the legs] during deceleration. (Hint: Draw that free-body ...
... knees in order to decelerate his torso on impact over a distance of 60cm. Bond’s torso’s mass is 45 kg. a. Calculate Bond’s velocity just before impact. b. Find the average acceleration [added later: and the average force on the torso due to the legs] during deceleration. (Hint: Draw that free-body ...
Uniform Circular Motion
... Figure 3b shows the velocity vectors at the two positions. Notice that the magnitude of the velocity vector is not changing. In Fig. 3c the two velocity vectors are redrawn, without changing their lengths or orientations. The arrow joining the tips of the velocity vectors represents the change ∆v in ...
... Figure 3b shows the velocity vectors at the two positions. Notice that the magnitude of the velocity vector is not changing. In Fig. 3c the two velocity vectors are redrawn, without changing their lengths or orientations. The arrow joining the tips of the velocity vectors represents the change ∆v in ...
on forces
... is zero the object continues in its original state of motion; if it was at rest, it remains at rest. If it was moving with a certain velocity, it will keep on moving with the same velocity. Second Law: The acceleration of an object is proportional to the net force acting on it, and inversely propo ...
... is zero the object continues in its original state of motion; if it was at rest, it remains at rest. If it was moving with a certain velocity, it will keep on moving with the same velocity. Second Law: The acceleration of an object is proportional to the net force acting on it, and inversely propo ...
Newton`s Laws of Motion
... watch it slide to a rest position. The book comes to a rest because of the presence of a force that force being the force of friction which brings the book to a rest position. ...
... watch it slide to a rest position. The book comes to a rest because of the presence of a force that force being the force of friction which brings the book to a rest position. ...
Final Exam Study Guide
... You are authorized to have a 3x5 card for the Final Exam. You may only use a handwritten 3x5 card. You will turn it in after the Exam. The Final Exam is 60 questions and you will have 90 minutes. There are no retakes for the Final Exam. Speed = Distance divided by time. If distance = zero, then spee ...
... You are authorized to have a 3x5 card for the Final Exam. You may only use a handwritten 3x5 card. You will turn it in after the Exam. The Final Exam is 60 questions and you will have 90 minutes. There are no retakes for the Final Exam. Speed = Distance divided by time. If distance = zero, then spee ...
Forces and Newton`s 3 Laws of Motion
... forces acting on an object are combined. It is necessary to find the net force when there are two or more forces acting on an object. If all of the forces acting on an object cancel each other out there is no net force and the forces are balanced. ...
... forces acting on an object are combined. It is necessary to find the net force when there are two or more forces acting on an object. If all of the forces acting on an object cancel each other out there is no net force and the forces are balanced. ...
Regular Note
... obvious mess in front of the face of the driver. This is a clear case of Newton's third law of motion. The firefly hit the bus and the bus hits the firefly. Which of the two forces is greater: the force on the firefly or the force on the bus? Trick Question! Each force is the same size. For every ac ...
... obvious mess in front of the face of the driver. This is a clear case of Newton's third law of motion. The firefly hit the bus and the bus hits the firefly. Which of the two forces is greater: the force on the firefly or the force on the bus? Trick Question! Each force is the same size. For every ac ...
Newtons 3rd Law of Motion
... b. Both forces exist at exactly the same time. They both start at exactly the same instant, and they both stop at exactly the same instant. They are equal in time. "opposite" means that the two forces always act in opposite DIRECTION - exactly 180o apart. ...
... b. Both forces exist at exactly the same time. They both start at exactly the same instant, and they both stop at exactly the same instant. They are equal in time. "opposite" means that the two forces always act in opposite DIRECTION - exactly 180o apart. ...
Transparancies for Dynamics
... Equations for (stationary) Alice’s position on boat w.r.t shore i.e. the co-ordinate transformation from frame S to S’ Assuming S and S’ coincide at t=0 : x x'vt Known as Gallilean transformations As we will see, these simple relations do not hold in y y' special relativity ...
... Equations for (stationary) Alice’s position on boat w.r.t shore i.e. the co-ordinate transformation from frame S to S’ Assuming S and S’ coincide at t=0 : x x'vt Known as Gallilean transformations As we will see, these simple relations do not hold in y y' special relativity ...
Online Education and Outreach
... change of motion, direction or speed.The amount of inertia depends upon the object’s mass. mass — The quantity of matter that is contained in an object.The more mass an object has, the greater weight it has in a gravitational field. Newton’s Cradle — A device with suspended, swinging steel balls tha ...
... change of motion, direction or speed.The amount of inertia depends upon the object’s mass. mass — The quantity of matter that is contained in an object.The more mass an object has, the greater weight it has in a gravitational field. Newton’s Cradle — A device with suspended, swinging steel balls tha ...
NCEA Level 2 Physics (91171) 2012 Assessment Schedule
... the centripetal force, is the difference between the tension force acting upwards and the gravity force acting vertically down. It is this unbalanced force that causes her to move in a circle. E7 1a + 2e ...
... the centripetal force, is the difference between the tension force acting upwards and the gravity force acting vertically down. It is this unbalanced force that causes her to move in a circle. E7 1a + 2e ...
