“How Things Work” – Lou Bloomfield Welcome to “How Things Work
... Why does a motionless skater tend to remain motionless? The short answer to that question is that an object at rest tends to remain at rest. In other words, if you leave a motionless skater completely alone, you don't push on her, she'll remain motionless and this is known as inertia and objects in ...
... Why does a motionless skater tend to remain motionless? The short answer to that question is that an object at rest tends to remain at rest. In other words, if you leave a motionless skater completely alone, you don't push on her, she'll remain motionless and this is known as inertia and objects in ...
CM2110 Chapter 2 - Chemical Engineering
... (English) (SI) Length ft m cm Mass lbm kg g Time s s s These are the base units. Some conversion factors are on the front cover of the text and on p. 11 Table 2.3-1. Another reference is the back cover of Perry’s Chemical Engineers Handbook. We’ll spend a lot of time in CM2110 converting between dif ...
... (English) (SI) Length ft m cm Mass lbm kg g Time s s s These are the base units. Some conversion factors are on the front cover of the text and on p. 11 Table 2.3-1. Another reference is the back cover of Perry’s Chemical Engineers Handbook. We’ll spend a lot of time in CM2110 converting between dif ...
Worked solutions Chapter 2: Collisions and
... When the car is at rest, its tendency as described by Newton’s first law is to remain at rest. A large force is needed to overcome its inertia and start the car rolling. Once the car is rolling, however, its tendency is to continue rolling. Only a small pushing force, to overcome resistance forces, ...
... When the car is at rest, its tendency as described by Newton’s first law is to remain at rest. A large force is needed to overcome its inertia and start the car rolling. Once the car is rolling, however, its tendency is to continue rolling. Only a small pushing force, to overcome resistance forces, ...
Motion and Potential Energy Graphs
... remains constant. This motion can be deduced by looking at the potential-energy graph using the two concepts outlined above. Initially KE = 0 and from the graph we see that P Eg = +7.5 J. Therefore ME = +7.5 J . However at point A there is a force acting because the slope is not zero. The object wil ...
... remains constant. This motion can be deduced by looking at the potential-energy graph using the two concepts outlined above. Initially KE = 0 and from the graph we see that P Eg = +7.5 J. Therefore ME = +7.5 J . However at point A there is a force acting because the slope is not zero. The object wil ...
Chapter 3 activity 1 instructions, summarizing questions
... Q5. Draw a force diagram for the 1000 g mass. Be sure that the arrows are sized appropriately when compared to the diagram you drew for the 100 gram mass. Q6. What do the sizes of t ...
... Q5. Draw a force diagram for the 1000 g mass. Be sure that the arrows are sized appropriately when compared to the diagram you drew for the 100 gram mass. Q6. What do the sizes of t ...
Physics Regents Review Sheet
... _____ the direction of centripetal acceleration and centripetal force _____ how to calculate the centripetal acceleration _____ how to calculate the centripetal force _____ how centripetal force and acceleration are related to radius _____ the direction of tangential velocity _____ how to calculate ...
... _____ the direction of centripetal acceleration and centripetal force _____ how to calculate the centripetal acceleration _____ how to calculate the centripetal force _____ how centripetal force and acceleration are related to radius _____ the direction of tangential velocity _____ how to calculate ...
kg·m
... Impulse Example An 8N force acts on a 5 kg object for 3 seconds. If the initial velocity of the object was 25 m/s, what is its final velocity? F= 8 N m= 5 kg t= 3 s v1 = 25 m/s v2 = ? J = Ft =(8N)(3s) = 24 N·s BUT we need to find v2 ……… ...
... Impulse Example An 8N force acts on a 5 kg object for 3 seconds. If the initial velocity of the object was 25 m/s, what is its final velocity? F= 8 N m= 5 kg t= 3 s v1 = 25 m/s v2 = ? J = Ft =(8N)(3s) = 24 N·s BUT we need to find v2 ……… ...
Momentum and Impulse
... 5. Impulse is defined as the force exerted on an object times the time it lasts. TRUE 6. Automobile seatbelts are used to lengthen the time of impact in case of a collision. TRUE 7. When a baseball player follows through when hitting the ball, the contact time with the ball is longer. TRUE 8. The mo ...
... 5. Impulse is defined as the force exerted on an object times the time it lasts. TRUE 6. Automobile seatbelts are used to lengthen the time of impact in case of a collision. TRUE 7. When a baseball player follows through when hitting the ball, the contact time with the ball is longer. TRUE 8. The mo ...
Gravity Questions
... become a black hole, the earth would a) leave the solar system in a straight-line path spiral b) spiral into the black hole c) undergo a major increase in tidal forces d) continue to circle in its usual orbit ...
... become a black hole, the earth would a) leave the solar system in a straight-line path spiral b) spiral into the black hole c) undergo a major increase in tidal forces d) continue to circle in its usual orbit ...