force
... Friction, Example 2 Draw the free-body diagram, including the force of kinetic friction. Opposes the motion Is parallel to the surfaces in contact Continue with the solution as with any Newton’s Law problem. This example gives information about ...
... Friction, Example 2 Draw the free-body diagram, including the force of kinetic friction. Opposes the motion Is parallel to the surfaces in contact Continue with the solution as with any Newton’s Law problem. This example gives information about ...
Rotational motion
... In the Yo-Yo problem, we saw that: Tension did positive rotational work (it made the Yo-Yo spin faster) Tension did negative translational work (it made the Yo-Yo move more slowly) ... the net work done by tension was zero. This happened because the string was stationary, and thus enforced a = ±αr. ...
... In the Yo-Yo problem, we saw that: Tension did positive rotational work (it made the Yo-Yo spin faster) Tension did negative translational work (it made the Yo-Yo move more slowly) ... the net work done by tension was zero. This happened because the string was stationary, and thus enforced a = ±αr. ...
Assignment 1 Chapter 5: Linear Forces
... In a modified "tug-of-war" game, two people pull in opposite directions, not on a rope, but on a 25-kg block resting on a smooth surface. The participants exert forces of 90 N and 92 N. (a) Draw a free body diagram of the forces on the block (b) What is the acceleration of the block? ANSWER ...
... In a modified "tug-of-war" game, two people pull in opposite directions, not on a rope, but on a 25-kg block resting on a smooth surface. The participants exert forces of 90 N and 92 N. (a) Draw a free body diagram of the forces on the block (b) What is the acceleration of the block? ANSWER ...
Dynamics Chapter
... However, there are some properties of mass that you will need to understand. 1. Mass is intrinsic to an object. It does not depend on where the object is located. No matter whether it is; on earth, in outer space or deep under the ocean, the mass of an object will not change. 2. An object’s accelera ...
... However, there are some properties of mass that you will need to understand. 1. Mass is intrinsic to an object. It does not depend on where the object is located. No matter whether it is; on earth, in outer space or deep under the ocean, the mass of an object will not change. 2. An object’s accelera ...
work and energy
... – Work depends on the path taken – Friction, air resistance, tension in a cord – Also called dissipative forces ...
... – Work depends on the path taken – Friction, air resistance, tension in a cord – Also called dissipative forces ...
physics VELOCITY, ACCELERATION, FORCE velocity
... For maximum or minimum problems that involve the point at which the object just begins to slide, you should always assume that the object does not slide, since this will allow you to use static friction, which obeys the inequality “ fs ≤ µ s n ”. (If you assumed that the object does slide, you wou ...
... For maximum or minimum problems that involve the point at which the object just begins to slide, you should always assume that the object does not slide, since this will allow you to use static friction, which obeys the inequality “ fs ≤ µ s n ”. (If you assumed that the object does slide, you wou ...
Exercises on Force and Motion Exercise 1.1 A small object is subject
... of 2 m/s2 . If a force of 14 Newtons is applied to the box, what will be it’s acceleration? If the 10 Newton force were the only one acting, the box would have an acceleration of a = 10/4 = 2.5 m/s2 . Since the acceleration is 2 m/s2 , the Net Force equals (4)(2) = 8 Newtons. There must be another f ...
... of 2 m/s2 . If a force of 14 Newtons is applied to the box, what will be it’s acceleration? If the 10 Newton force were the only one acting, the box would have an acceleration of a = 10/4 = 2.5 m/s2 . Since the acceleration is 2 m/s2 , the Net Force equals (4)(2) = 8 Newtons. There must be another f ...
Slide 1
... 3. A 0.20 kg object moves along a straight line. The net force acting on the object varies with the object’s displacement as shown. The object starts from rest at displacement x = 0 and time t = 0 and is displaced a distance of 20 m. Determine each of the following. a. The accl of the particle when ...
... 3. A 0.20 kg object moves along a straight line. The net force acting on the object varies with the object’s displacement as shown. The object starts from rest at displacement x = 0 and time t = 0 and is displaced a distance of 20 m. Determine each of the following. a. The accl of the particle when ...
Noah Newton`s 2nd Law on Hills Class Exercises
... 2. Jimmy is going to pull his 1000 kg motorboat out of the water and up the 18° slope of the boat ramp. i. Jimmy’s truck and boat trailer are parked on the boat ramp, 10 m uphill from the water. He gets in the truck, eases off the brake, and allows the trailer to accelerate all the way down the ram ...
... 2. Jimmy is going to pull his 1000 kg motorboat out of the water and up the 18° slope of the boat ramp. i. Jimmy’s truck and boat trailer are parked on the boat ramp, 10 m uphill from the water. He gets in the truck, eases off the brake, and allows the trailer to accelerate all the way down the ram ...
Chapter 6 practice questions
... a) 60 J b) 80 J c) 100 J d) 120 J e) 140 J Ans: a 2) A 30.0 kg box slides up a 12.0 meters long incline at an angle of 30 degrees above the horizontal. The change in gravitational potential energy is, a) 21 J b) 14 J c) 10 J d) 6 J e) 4 J Ans: d (1764 J) 3) A horizontal force is applied to a 4.0 kg ...
... a) 60 J b) 80 J c) 100 J d) 120 J e) 140 J Ans: a 2) A 30.0 kg box slides up a 12.0 meters long incline at an angle of 30 degrees above the horizontal. The change in gravitational potential energy is, a) 21 J b) 14 J c) 10 J d) 6 J e) 4 J Ans: d (1764 J) 3) A horizontal force is applied to a 4.0 kg ...
Rotary Homework #1
... kg, and the magnitude of the force acting on it as it settles out of the plasma is 4.0 × 10–11 N. At how many revolutions per second should the centrifuge be operated? 11. A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 32.0 m/s. With what maximum sp ...
... kg, and the magnitude of the force acting on it as it settles out of the plasma is 4.0 × 10–11 N. At how many revolutions per second should the centrifuge be operated? 11. A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 32.0 m/s. With what maximum sp ...
NEWTON`S LAWS OF MOT ION, FRICTION
... µk = Coeff. of kinetic friction . It depends on surfaces in contact. N = Normal reaction Note: Generally, it may be easier to apply kinetic friction concept while solving problems. But, one needs to be more careful while applying static friction concept, as it is a self-adjusting force. While solvin ...
... µk = Coeff. of kinetic friction . It depends on surfaces in contact. N = Normal reaction Note: Generally, it may be easier to apply kinetic friction concept while solving problems. But, one needs to be more careful while applying static friction concept, as it is a self-adjusting force. While solvin ...
