Chapter 1
... second. Having established that, we easily find that in two similar right triangles, the ratio of each side to another in one triangle is equal to the ratio between the two corresponding sides of the other triangle. It is no long stretch from there to realize that this must be true of all similar tr ...
... second. Having established that, we easily find that in two similar right triangles, the ratio of each side to another in one triangle is equal to the ratio between the two corresponding sides of the other triangle. It is no long stretch from there to realize that this must be true of all similar tr ...
Fallacies in Mathematics
... 'but the whole is greater than its part', so that the result follows. There is, however, no step in the argument which proves from earlier results which is the whole and which the part. The only reason for selecting LPCA as the whole is that it 'looks like it'; but whether it would continue to do so ...
... 'but the whole is greater than its part', so that the result follows. There is, however, no step in the argument which proves from earlier results which is the whole and which the part. The only reason for selecting LPCA as the whole is that it 'looks like it'; but whether it would continue to do so ...
Circle theorems - Cambridge University Press
... ∠AOB = 2a ◦ + 2b◦ = 2(a + b)◦ = 2∠APB Note: In the proof presented above, the centre and point P are considered to be on the same side of chord AB. The proof is not dependent on this and the result always holds. The converse of this result also holds: i.e., if A and B are points on a circle with cen ...
... ∠AOB = 2a ◦ + 2b◦ = 2(a + b)◦ = 2∠APB Note: In the proof presented above, the centre and point P are considered to be on the same side of chord AB. The proof is not dependent on this and the result always holds. The converse of this result also holds: i.e., if A and B are points on a circle with cen ...
Given - mendeleev08-09
... Given: n is perpendicular to m, s is perpendicular to m Prove: n is parallel to s Proof: Statements 1. n is perpendicular to m, s is perpendicular to m 2. h, g are right angles ...
... Given: n is perpendicular to m, s is perpendicular to m Prove: n is parallel to s Proof: Statements 1. n is perpendicular to m, s is perpendicular to m 2. h, g are right angles ...
Sample Documents Geometry
... Copyright (c) 1999 EAS EducAide Software Inc. All rights reserved. You may distribute this document freely, provided you do not alter it in any way or remove this copyright notice. Note: this document was produced by EducAide’s Acces program. It contains problems from the GEO database. For more info ...
... Copyright (c) 1999 EAS EducAide Software Inc. All rights reserved. You may distribute this document freely, provided you do not alter it in any way or remove this copyright notice. Note: this document was produced by EducAide’s Acces program. It contains problems from the GEO database. For more info ...
Linear Equations
... Complementary angles do not have to share the same vertex or a common side. Meaning, complementary angles do not have to be adjacent. Definition of Supplementary Angles: Two angles are supplementary if and only if the sum of their degree measures is 180. If two angles are supplementary, then each is ...
... Complementary angles do not have to share the same vertex or a common side. Meaning, complementary angles do not have to be adjacent. Definition of Supplementary Angles: Two angles are supplementary if and only if the sum of their degree measures is 180. If two angles are supplementary, then each is ...
4-4 Isoceles Triangles, Corollaries and CPCTC
... When you use a shortcut (SSS, AAS, SAS, ASA, HL) to show that 2 triangles are congruent, that means that ALL the corresponding parts are congruent. EX: If a triangle is congruent by ASA (for instance), then all the other corresponding parts are congruent. ...
... When you use a shortcut (SSS, AAS, SAS, ASA, HL) to show that 2 triangles are congruent, that means that ALL the corresponding parts are congruent. EX: If a triangle is congruent by ASA (for instance), then all the other corresponding parts are congruent. ...
