Calculus, Circle Geometry and RUGBY KICKS
... 5.6x × 2x = 5.6(x2 + 512) x2 = 512 x = 16√2 ≈ 22.6m However, the same result can be reached using simple CIRCLE GEOMETRY. Imagine a circle which passes through P and Q with TB a tangent at B. Clearly PBQ = θ is the largest angle because if we consider other points on TB at, say, L and M, the angles ...
... 5.6x × 2x = 5.6(x2 + 512) x2 = 512 x = 16√2 ≈ 22.6m However, the same result can be reached using simple CIRCLE GEOMETRY. Imagine a circle which passes through P and Q with TB a tangent at B. Clearly PBQ = θ is the largest angle because if we consider other points on TB at, say, L and M, the angles ...
