C SETS - UH - Department of Mathematics
... 1. The set of vowels in the word “probability” is the set C = {a, o, i}. Note that the letter i appears twice in the word “probability” but we list it once - a set is a collection of distinct elements. 2. The set of real numbers that satisfy the equation x 2 − 9 = 0 is the set S = {− 3,3} . 3. The s ...
... 1. The set of vowels in the word “probability” is the set C = {a, o, i}. Note that the letter i appears twice in the word “probability” but we list it once - a set is a collection of distinct elements. 2. The set of real numbers that satisfy the equation x 2 − 9 = 0 is the set S = {− 3,3} . 3. The s ...
15_cardinality
... The inverse of a bijective function f : A → B is the unique function f ‑1: B → A such that for any a ∈ A, f ‑1(f(a)) = a and for any b ∈ B, f(f ‑1(b)) = b A function is bijective if it has an inverse function f(a) ...
... The inverse of a bijective function f : A → B is the unique function f ‑1: B → A such that for any a ∈ A, f ‑1(f(a)) = a and for any b ∈ B, f(f ‑1(b)) = b A function is bijective if it has an inverse function f(a) ...
FIRST DEGREE ENTAILMENT, SYMMETRY AND PARADOX
... the following sequents are not valid in fde, but they are valid in lp: ...
... the following sequents are not valid in fde, but they are valid in lp: ...
Full text
... multiplicative arithmetical functions, for example the Moebius function, can be defined and theorems, such as the Moebius inversion formula for g.i., can be proved. Much of this work has been carried out by the author. However, for his work, Beurling needed an assumption on the size of N(x) . He and ...
... multiplicative arithmetical functions, for example the Moebius function, can be defined and theorems, such as the Moebius inversion formula for g.i., can be proved. Much of this work has been carried out by the author. However, for his work, Beurling needed an assumption on the size of N(x) . He and ...
1. Problems and Results in Number Theory
... X and I asked : Are there infinitely many 2k-tuples (k > 1) of consecutive primes pn +i < • • • < pn+2k satisfying pn+i + t = pn+k+i' for some t = t(k) and i = 1, . . . , k? The prime k-tuple conjecture of course implies this ; the point is to try to prove this without any hypotheses . We were unabl ...
... X and I asked : Are there infinitely many 2k-tuples (k > 1) of consecutive primes pn +i < • • • < pn+2k satisfying pn+i + t = pn+k+i' for some t = t(k) and i = 1, . . . , k? The prime k-tuple conjecture of course implies this ; the point is to try to prove this without any hypotheses . We were unabl ...
Default Reasoning in a Terminological Logic
... applicative interest, as they are specifically oriented to the vast class of application domains that are describable by means of taxonomic organizations of complex objects. Although the field of TLs has lately been an active area of investigation, only few researchers have addressed the problem of ex ...
... applicative interest, as they are specifically oriented to the vast class of application domains that are describable by means of taxonomic organizations of complex objects. Although the field of TLs has lately been an active area of investigation, only few researchers have addressed the problem of ex ...
Automata vs. Logics on Data Words
... into equivalent automaton-based specifications, easing, in this way, the various reasoning tasks. Different models of automata which process words over infinite alphabets have been proposed and studied in the literature (see, for instance, the surveys [6, 7]). Pebble automata [8] use special markers ...
... into equivalent automaton-based specifications, easing, in this way, the various reasoning tasks. Different models of automata which process words over infinite alphabets have been proposed and studied in the literature (see, for instance, the surveys [6, 7]). Pebble automata [8] use special markers ...
Chapter 5 of my book
... A ∩ {1, 2, . . . , N }, and consider limN →∞ ANN . Such comparisons allowed us to show that in the limit zero percent of all integers are prime (see Chebyshev’s Theorem, Theorem ??), but there are far more primes than perfect squares. While such limiting arguments work well for subsets of the intege ...
... A ∩ {1, 2, . . . , N }, and consider limN →∞ ANN . Such comparisons allowed us to show that in the limit zero percent of all integers are prime (see Chebyshev’s Theorem, Theorem ??), but there are far more primes than perfect squares. While such limiting arguments work well for subsets of the intege ...