Experiment 4: Damped Oscillations and Resonance in RLC Circuits
... v vs. t, f = 9000 Hz (R = 1500 Ω , L = 70 mH, C = 0.0015 µF) ...
... v vs. t, f = 9000 Hz (R = 1500 Ω , L = 70 mH, C = 0.0015 µF) ...
www.BDTIC.com/ON/ Test Procedure for the NCP1562 Evaluation Board
... 1. Configure Multimeter 1 (MM1) for measuring current. Connect Power Supply (+) terminal to MM1 current measurement terminal. 2. Connect MM1 ground terminal to demo board (Vin+) terminal. 3. Connect Power Supply (-) terminal to demo board (Vin-) terminal. 4. Configure Multimeter 2 (MM2) for measurin ...
... 1. Configure Multimeter 1 (MM1) for measuring current. Connect Power Supply (+) terminal to MM1 current measurement terminal. 2. Connect MM1 ground terminal to demo board (Vin+) terminal. 3. Connect Power Supply (-) terminal to demo board (Vin-) terminal. 4. Configure Multimeter 2 (MM2) for measurin ...
I consumer
... Specific problems with the non-linear consumers by the usage of welding device, containing controlled electric arc, protection does not function, i. e. have to be blocked microwave has the fifth harmonic of 45.5 % I5g; the microwave decrease the total fifth harmonic appearing in parallel connecti ...
... Specific problems with the non-linear consumers by the usage of welding device, containing controlled electric arc, protection does not function, i. e. have to be blocked microwave has the fifth harmonic of 45.5 % I5g; the microwave decrease the total fifth harmonic appearing in parallel connecti ...
Alternative energy lab handout
... reasonable lengths of it have near to zero resistance to the passage of electrons from one end to the other. It is possible to get some materials to become super conducting at very low temperatures (4 - 77 K). A super conductor actually has no resistance at all; thus none of the energy carried by th ...
... reasonable lengths of it have near to zero resistance to the passage of electrons from one end to the other. It is possible to get some materials to become super conducting at very low temperatures (4 - 77 K). A super conductor actually has no resistance at all; thus none of the energy carried by th ...
Electricity Lab - New Haven Science
... Another way to describe the operation of the motor is to say that the permanent magnets exert forces on the electrical currents flowing through the loop of wire. When the loop of wire is in a vertical plane, the forces on the top and bottom wires of the loop will be in opposite directions. These opp ...
... Another way to describe the operation of the motor is to say that the permanent magnets exert forces on the electrical currents flowing through the loop of wire. When the loop of wire is in a vertical plane, the forces on the top and bottom wires of the loop will be in opposite directions. These opp ...
Back EMF in a Motor
... An electric motor has the same design as a generator; the latter changes mechanical energy to electrical energy and the former, vice versa. • A current in the armature of a motor turns in the magnetic field according to the RHR, with Fmag creating the necessary torque. • BUT the turning armature, by ...
... An electric motor has the same design as a generator; the latter changes mechanical energy to electrical energy and the former, vice versa. • A current in the armature of a motor turns in the magnetic field according to the RHR, with Fmag creating the necessary torque. • BUT the turning armature, by ...
Solutions to Homework problems Chapters 18-20.
... shown at the right. The diagram shows the attractive force F from each negative charge directed along the lines between the charges. Only when each force has the same magnitude (which is the case when both unknown charges have the same magnitude) will the resultant force point vertically downward. T ...
... shown at the right. The diagram shows the attractive force F from each negative charge directed along the lines between the charges. Only when each force has the same magnitude (which is the case when both unknown charges have the same magnitude) will the resultant force point vertically downward. T ...
End Semester Examination-2004
... 3. The primary resistance and leakage reactance is not neglected in the CT equivalent circuit. 4. The capacitance graded voltage transformer is used for low voltage applications. 5. In a capacitance graded voltage transformer the inductor is tuned to resonate at 5th harmonic frequency. 6. Generator ...
... 3. The primary resistance and leakage reactance is not neglected in the CT equivalent circuit. 4. The capacitance graded voltage transformer is used for low voltage applications. 5. In a capacitance graded voltage transformer the inductor is tuned to resonate at 5th harmonic frequency. 6. Generator ...
Home Voltage Stabilizer / Regulator - Ashley
... In order for us to be able to offer the most cost efficient voltage stabiliser solution there are always 6 Key Questions which we must ask a client before we can make a suitable recommendation. ...
... In order for us to be able to offer the most cost efficient voltage stabiliser solution there are always 6 Key Questions which we must ask a client before we can make a suitable recommendation. ...
Biophysics Notes Chapter 9
... I = IL = gL (Vm – VL), VL < Vresting (-60 mV) 2. Voltage steps – depolarizing V Do overview at end briefly first Depolarization early negative current late positive current As V increases The amplitide of the negative current decreases At V = 117, (Vm = 57 mV), I neg = 0 If V > 117 mV get ...
... I = IL = gL (Vm – VL), VL < Vresting (-60 mV) 2. Voltage steps – depolarizing V Do overview at end briefly first Depolarization early negative current late positive current As V increases The amplitide of the negative current decreases At V = 117, (Vm = 57 mV), I neg = 0 If V > 117 mV get ...
UNIT-1 - IEC GUIDE
... signals with modulation indices 0.6, 0.3 and 0.4 respectively. 5. A carrier of 10 V peak and frequency 100 kHz is amplitude modulated by a sine wave of 4v peak and frequency 1000Hz. Determine the modulation index for the modulated wave. 6. 400 watt carrier is modulated to a depth of 80%.calculate th ...
... signals with modulation indices 0.6, 0.3 and 0.4 respectively. 5. A carrier of 10 V peak and frequency 100 kHz is amplitude modulated by a sine wave of 4v peak and frequency 1000Hz. Determine the modulation index for the modulated wave. 6. 400 watt carrier is modulated to a depth of 80%.calculate th ...
Sensing Distance (SHARP GP2Y0A21YK)
... and ground and a voltage proportional to the distance between the sensor and an object in front of it will be returned (ranging from 0.4 volts at 80 cm to 3 volts at 10 cm). It really couldn't be simpler to use. Converting to Distance The voltage returned is not linear (see graph), however it can be ...
... and ground and a voltage proportional to the distance between the sensor and an object in front of it will be returned (ranging from 0.4 volts at 80 cm to 3 volts at 10 cm). It really couldn't be simpler to use. Converting to Distance The voltage returned is not linear (see graph), however it can be ...
Zetex - DN78, ZXSC310 with reverse polarity protection
... The schematic diagram shown in Figure 1 is a typical example of the ZXSC310 used in a LED flashlight application. The input voltage can either be one or two alkaline cells. If the battery is put in the flashlight the wrong way, the reverse polarity can damage the ZXSC310 and switching transistor, Q1 ...
... The schematic diagram shown in Figure 1 is a typical example of the ZXSC310 used in a LED flashlight application. The input voltage can either be one or two alkaline cells. If the battery is put in the flashlight the wrong way, the reverse polarity can damage the ZXSC310 and switching transistor, Q1 ...
Laplace Transform
... •We determine the initial conditions of the circuit (current through the inductors, voltages on capacitors) before switching action. •We draw the equivalent operational circuit, containing the Laplace transform of given sources, the sources corresponding to initial conditions, operational impedances ...
... •We determine the initial conditions of the circuit (current through the inductors, voltages on capacitors) before switching action. •We draw the equivalent operational circuit, containing the Laplace transform of given sources, the sources corresponding to initial conditions, operational impedances ...
AVR120-6 - ElectricalManuals.net
... load may be due to speed change from no load to full load, causing the frequency compensation (V/Hz) circuit to reduce voltage at lower frequencies. ...
... load may be due to speed change from no load to full load, causing the frequency compensation (V/Hz) circuit to reduce voltage at lower frequencies. ...
Series A dV/dt Filters
... rating of 100% RMS, with intermittent current ratings of 150% for 1 minute and 200% for 10 seconds. PRODUCT SELECTION: See MTE dV/dt Filter Selection Brochure or visit the MTE website at www.mtecorp.com for complete product selection. Please note that Series A dV/dt Filters can only be used with PWM ...
... rating of 100% RMS, with intermittent current ratings of 150% for 1 minute and 200% for 10 seconds. PRODUCT SELECTION: See MTE dV/dt Filter Selection Brochure or visit the MTE website at www.mtecorp.com for complete product selection. Please note that Series A dV/dt Filters can only be used with PWM ...
Bip Transistor 15V 0.7A VCE(sat);35mV max. PNP Single CP
... customer' s products or equipment. To verify symptoms and states that cannot be evaluated in an independent device, the customer should always evaluate and test devices mounted in the customer' s products or equipment. SANYO Semiconductor Co.,Ltd. assumes no responsibility for equipment failures tha ...
... customer' s products or equipment. To verify symptoms and states that cannot be evaluated in an independent device, the customer should always evaluate and test devices mounted in the customer' s products or equipment. SANYO Semiconductor Co.,Ltd. assumes no responsibility for equipment failures tha ...
