
Slide 1
... To decipher k, how many values do we need to try ? Why ? i mod n = (i + kn) mod n for all integers k. ...
... To decipher k, how many values do we need to try ? Why ? i mod n = (i + kn) mod n for all integers k. ...
Non-standard number representation: computer arithmetic, beta
... We refer the reader to [17] and to [42]. An alphabet A is a finite set. A finite sequence of elements of A is called a word, and the set of words on A is the free monoid A∗ . The empty word is denoted by ε. The set of infinite sequences or infinite words on A is denoted by AN . Let v be a word of A∗ ...
... We refer the reader to [17] and to [42]. An alphabet A is a finite set. A finite sequence of elements of A is called a word, and the set of words on A is the free monoid A∗ . The empty word is denoted by ε. The set of infinite sequences or infinite words on A is denoted by AN . Let v be a word of A∗ ...
Full text
... disjoint coverings generated by linear recurrences of every order n. In the case of the Fibonacci recurrence un+2 =un+i + urn they constructed a regular covering which is not disjoint and asked whether a disjoint covering in this case exists as well. The following theorem answers this ...
... disjoint coverings generated by linear recurrences of every order n. In the case of the Fibonacci recurrence un+2 =un+i + urn they constructed a regular covering which is not disjoint and asked whether a disjoint covering in this case exists as well. The following theorem answers this ...