
Intersection Theory course notes
... Motivation. Intersection theory had been developed mainly in order to give a rigorous foundation for methods of enumerative geometry. Here is a typical question considered in enumerative geometry. How many lines in 3-space intersect 4 given lines in general position? Here is Schubert’s solution. Ch ...
... Motivation. Intersection theory had been developed mainly in order to give a rigorous foundation for methods of enumerative geometry. Here is a typical question considered in enumerative geometry. How many lines in 3-space intersect 4 given lines in general position? Here is Schubert’s solution. Ch ...
New Insights Into Emission Tomography Via Linear Programming
... Suppose that each detector unit, d, of an emission scanner measures a count n'(d) which represents the number of emissions into d of an unknown emission density "- . The likelihood, P (n' I,,-), is the (Poisson) probability of observing n' under ).. The well-known EM algorithm starts with an estimat ...
... Suppose that each detector unit, d, of an emission scanner measures a count n'(d) which represents the number of emissions into d of an unknown emission density "- . The likelihood, P (n' I,,-), is the (Poisson) probability of observing n' under ).. The well-known EM algorithm starts with an estimat ...
Full text
... Since Nr(o)j) is an integer, fi must be a multiple of 8, which will turn out to be impossible unless all Cjh are even, a case already excluded. In fact, taking the congruence modulo 2 of the expression between square brackets, we find the condition CjX + Cj2 + Cj3 = 0, j = 1,2,3, where, for at least ...
... Since Nr(o)j) is an integer, fi must be a multiple of 8, which will turn out to be impossible unless all Cjh are even, a case already excluded. In fact, taking the congruence modulo 2 of the expression between square brackets, we find the condition CjX + Cj2 + Cj3 = 0, j = 1,2,3, where, for at least ...