
Solutions to Homework 7 27. (Dummit
... clearly non-zero. Since K is a field it has no non-zero ideals and thus our map is injective. Since it is obviously surjective, we are done. (Dummit-Foote 13.2 #22) Let {αi } be a basis for K1 over F , and let {βj } be a basis for K2 over F . Then {αi ⊗ βj } is a basis for K1 ⊗F K2 over F . Define a ...
... clearly non-zero. Since K is a field it has no non-zero ideals and thus our map is injective. Since it is obviously surjective, we are done. (Dummit-Foote 13.2 #22) Let {αi } be a basis for K1 over F , and let {βj } be a basis for K2 over F . Then {αi ⊗ βj } is a basis for K1 ⊗F K2 over F . Define a ...
1 - USC
... 1. What are the essential characteristics of problems that can be solved by greedy algorithms? 2. The CS department wishes to allocate some courses to SAL 101. The list of courses are: Courses: ...
... 1. What are the essential characteristics of problems that can be solved by greedy algorithms? 2. The CS department wishes to allocate some courses to SAL 101. The list of courses are: Courses: ...