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... The complex number system enables us to take even roots of negative numbers by means of the imaginary unit i, which is equal to the square root of –1; that is i2 = -1 and i = 1 . By factoring –1 out of a negative expression, it becomes positive and an even root can be taken: -b = i b . Standard for ...
... The complex number system enables us to take even roots of negative numbers by means of the imaginary unit i, which is equal to the square root of –1; that is i2 = -1 and i = 1 . By factoring –1 out of a negative expression, it becomes positive and an even root can be taken: -b = i b . Standard for ...
Test 2 Working with Polynomials
... Donkey Kong is competing in a shot-put challenge at the Olympics. His throw can be modeled by the function h(t) = -5t2 + 8.5t + 1.8, where h is the height, in metres, of a shot-put t seconds after it is thrown. Determine the remainder when h(t) is divided by (t – 1.4). What does this value represent ...
... Donkey Kong is competing in a shot-put challenge at the Olympics. His throw can be modeled by the function h(t) = -5t2 + 8.5t + 1.8, where h is the height, in metres, of a shot-put t seconds after it is thrown. Determine the remainder when h(t) is divided by (t – 1.4). What does this value represent ...
aa2.pdf
... 5. Let s, u ∈ Mm (k) be a pair of commuting matrices such that s is a diagonal matrix and u is a strictly upper triangular matrix (with zeros at the diagonal). Put a = s + u. Show that there exists a polynomial f (x) = c1 · x + . . . + cd · xd ∈ k[x], without constant term and such that one has s = ...
... 5. Let s, u ∈ Mm (k) be a pair of commuting matrices such that s is a diagonal matrix and u is a strictly upper triangular matrix (with zeros at the diagonal). Put a = s + u. Show that there exists a polynomial f (x) = c1 · x + . . . + cd · xd ∈ k[x], without constant term and such that one has s = ...
