Newtons` First and Second Laws
... Students will have learned about Newton’s First Law of motion already so it is a good time to tie things in. In order to get an object in motion (accelerate) we need a force. No acceleration requires no force. However because of friction a small amount of force must be applied to overcome friction i ...
... Students will have learned about Newton’s First Law of motion already so it is a good time to tie things in. In order to get an object in motion (accelerate) we need a force. No acceleration requires no force. However because of friction a small amount of force must be applied to overcome friction i ...
Dynamics and Space
... 33. Calculate the amount of heat energy required to melt 0.3 kg of ice at 0 oC. (Specific latent heat of fusion of ice = 3.34 x 105 Jkg-1) 34. Calculate the specific latent heat of fusion of naphthalene given that 6 x 105 J of heat are given out when 4.0 kg of naphthalene at its melting point change ...
... 33. Calculate the amount of heat energy required to melt 0.3 kg of ice at 0 oC. (Specific latent heat of fusion of ice = 3.34 x 105 Jkg-1) 34. Calculate the specific latent heat of fusion of naphthalene given that 6 x 105 J of heat are given out when 4.0 kg of naphthalene at its melting point change ...
12 momentum impulse mc key File
... The plastic ball is clearly lighter so anything involving mass is out, this leaves speed which makes sense based on free-fall ...
... The plastic ball is clearly lighter so anything involving mass is out, this leaves speed which makes sense based on free-fall ...
Assessment No 02 5 th Term
... having cross sectional area of 1000mm2 . If the density of water is 1000Kgm-3 the gravitational force is 10ms-2 , and the power of the pump. If this stream of water hits to a vertical wall with this same speed and if there is no any bouncing, find the thrust occur on the wall. 02) One side of an ine ...
... having cross sectional area of 1000mm2 . If the density of water is 1000Kgm-3 the gravitational force is 10ms-2 , and the power of the pump. If this stream of water hits to a vertical wall with this same speed and if there is no any bouncing, find the thrust occur on the wall. 02) One side of an ine ...
Product Instructions: Inclined Plane
... For a normal balance, the two masses would need to be the same in order for the system to be in equilibrium. However, only a component of the weight of 1 is acting to pull it down the incline, so the mass of 2 only need be equal and opposite to the component of 1 acting along the incline. ...
... For a normal balance, the two masses would need to be the same in order for the system to be in equilibrium. However, only a component of the weight of 1 is acting to pull it down the incline, so the mass of 2 only need be equal and opposite to the component of 1 acting along the incline. ...
Physics_1996_Paper_I_+_ANS
... 3. (a) A boy 1.5 m tall stands a few metres in front of a plane mirror AB which is hung on a vertical wall. The boy’s eyes are 1.4 m above the ground . He can see all of himself in the mirror. In Figure 5, PQ represents the boy and E denotes his eyes. i. ...
... 3. (a) A boy 1.5 m tall stands a few metres in front of a plane mirror AB which is hung on a vertical wall. The boy’s eyes are 1.4 m above the ground . He can see all of himself in the mirror. In Figure 5, PQ represents the boy and E denotes his eyes. i. ...
Moment of inertia
... To see why I = M hr2 i, let’s consider the kinetic energy of a spinning object. The kinetic energy of a single “point mass” moving in a circle is 12 mv 2 = 12 mr2 ω 2 , where r is its distance from the center. Since KErot = 12 Iω 2 , this means I = mr2 for a single point. For an extended object, we ...
... To see why I = M hr2 i, let’s consider the kinetic energy of a spinning object. The kinetic energy of a single “point mass” moving in a circle is 12 mv 2 = 12 mr2 ω 2 , where r is its distance from the center. Since KErot = 12 Iω 2 , this means I = mr2 for a single point. For an extended object, we ...
3-18 IOT - Review 4 - Trig_ Vectors_ Work
... 4. You exerted a force to support the book, but you did not move it. 5. A force does no work if the object doesn’t move IOT ...
... 4. You exerted a force to support the book, but you did not move it. 5. A force does no work if the object doesn’t move IOT ...
Document
... C. The density of the lines (the number per unit area perpendicular to the lines) is proportional to the magnitude of the field at that point. D. Electric field lines cross midway between charges that have equal magnitude and sign. E. The direction of each line indicates the direction that a positiv ...
... C. The density of the lines (the number per unit area perpendicular to the lines) is proportional to the magnitude of the field at that point. D. Electric field lines cross midway between charges that have equal magnitude and sign. E. The direction of each line indicates the direction that a positiv ...
