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Profile Documents Logout
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C f dr
C f dr

... In Theorem 4 we needed an open connected region. For the next theorem we need a stronger condition. A simply-connected region in the plane is a connected region D such that every simple closed curve in D encloses only points that are in D. Notice from Figure 7 that, intuitively speaking, a ...
Gravity Investigation
Gravity Investigation

The Equilibrium of Forces: The First Law
The Equilibrium of Forces: The First Law

... F 1x A similar expression can be written for the y-components of the forces, except that the cosine appearing in Eq. (3) is replaced with the sine. EXERCISES: 1. Determine the resultant force of two vectors a number of times. a. On the equilibrium-of-forces apparatus, i) Choose arbitrary directions ...
The Wave Equation & Velocity
The Wave Equation & Velocity

... Read for Mon 2 Feb: S&W 53-62 (§2.4); 458-462 ...
Forces of Friction
Forces of Friction

Tuesday, June 6, 2006
Tuesday, June 6, 2006

... object. To move faster, ones needs higher force. Galileo’s statement on natural states of matter: Any velocity once imparted to a moving body will be rigidly maintained as long as the external causes of retardation are removed!! Galileo’s statement is formulated by Newton into the 1st law of motion ...
Chapter 2 Summary
Chapter 2 Summary

... • The mass of an object is a measure of the amount of matter it contains • SI unit of mass is kg • Mass is an intrinsic property of an object • It is independent of the object’s location • It is independent of the object’s velocity or ...
Part VI
Part VI

... • Forces exerted BY an object DO NOT (directly) influence its motion!! • Forces exerted ON an object (BY some other object) DO influence its motion!! • When discussing forces, use the words “BY” and “ON” carefully. ...
Kinetic Energy and Work
Kinetic Energy and Work

... We can use the equation above to define the SI unit for work (the joule, symbol: J ). An object of mass m = 1kg that moves with speed v = 1 m/s has a kinetic energy K = 1J. Work: (symbol W) If a force F is applied to an object of mass m it can accelerate it and increase its speed v and kinetic energ ...
Torque and rotational inertia
Torque and rotational inertia

Lecture 7.Kinds_of_F..
Lecture 7.Kinds_of_F..

Acceleration Due to Gravity
Acceleration Due to Gravity

pulley
pulley

... lever will also be equal. ...
Gravitation and Grav fields
Gravitation and Grav fields

Learning Goals/Success Criteria for Forces
Learning Goals/Success Criteria for Forces

Newton`s law
Newton`s law

PHYS 1443 – Section 501 Lecture #1
PHYS 1443 – Section 501 Lecture #1

... F G  ma  m g Weight of an object with mass M is W  F G  M g  Mg Since weight depends on the magnitude of gravitational acceleration, g, it varies depending on geographical location. By measuring the forces one can determine masses. This is why you ...
Dynamics Presentation
Dynamics Presentation

... An object sliding down an incline has three forces acting on it: the normal force, gravity, and the frictional force. • The normal force is always perpendicular to the surface. • The friction force is parallel to it. • The gravitational force points down. If the object is at rest, the forces are the ...
- Review the relationship between force and acceleration
- Review the relationship between force and acceleration

... 2) If there’s a curve, there’s an acceleration. 3) Curved “valley” is forward (positive) acceleration, a curved “hill” is backward (negative) acceleration. ...
Here - UCSB HEP
Here - UCSB HEP

Newton`s Laws of Motion
Newton`s Laws of Motion

posted
posted

... EVALUATE: A graphical sketch of the vector sum should agree with the results found in (b). Adding the forces as vectors gives a very different result from adding their magnitudes. IDENTIFY: We know the resultant of two vectors of equal magnitude and want to find their magnitudes. They make the same ...
PhysicsMCExamReview-SPG2015
PhysicsMCExamReview-SPG2015

... 104. What is the force of gravitational attraction between the Earth, with a mass of 5.98x1024 kg, and another planet with a mass of 1.5x1018 kg? The distance between them is 1.5x1030 m. A) 1.5x1020 N B) 6.67x10-11 N C) 3.8x10-15N D) 2.66x10-28 N 105. A 5 kg object initially at rest has a 10 N force ...
perepared by: m ziaulhaq ccet - Chendu College of Engineering
perepared by: m ziaulhaq ccet - Chendu College of Engineering

... are shown including support reactions example:consider a ladder of weight W having rollers at it’s end’s as shown in figure. 11.Statethe necessary and sufficient conditions for equilibrium of rigid bodies in two dimensions? The necessary and sufficient conditions for equilibrium of rigid bodies in t ...
Chapter 4: Newton`s Laws of Motion
Chapter 4: Newton`s Laws of Motion

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Centripetal force

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