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Unit 5 Notes
Unit 5 Notes

... Force is in Newtons. Remember that a Newton is a kilogram meter per second squared: 1N = 1kgm/s2 If we multiply the unit Newton by the unit seconds, we get a kilogram meter per second. This is the same as the unit for momentum. Therefore, the impulse delivered to an object is equal to the change in ...
TE0011_1_Force Expectations at Key Stage 2 Sc4 2 FORCES
TE0011_1_Force Expectations at Key Stage 2 Sc4 2 FORCES

... In the first instance, the object is stationary, held in place – with gravity being the only other force acting on it. As it released, the sudden massive imbalance of forces causes the object to accelerate towards the ground. As it starts to move, it pushes through the air causing air resistance whi ...
Force & Motion
Force & Motion

... Acceleration = change in velocity acceleration = velocity ÷ time (a = v ÷ t) ...
Exams are arranged in alphabebcal order by last name
Exams are arranged in alphabebcal order by last name

Chapter 4 Forces and Newton’s Laws of Motion continued
Chapter 4 Forces and Newton’s Laws of Motion continued

... 2) Use Newton’s 2nd law, to calculate the frictional force that must act on the mass. ...
Slide 1
Slide 1

Lesson 15 - Magnetic Fields II
Lesson 15 - Magnetic Fields II

PWE 8-12: A Simple Pulley I
PWE 8-12: A Simple Pulley I

Chapter 7 Impulse and Momentum
Chapter 7 Impulse and Momentum

Chapter 4: Newton`s Second Law of Motion
Chapter 4: Newton`s Second Law of Motion

Handout 5: Oscillatory motion Simple harmonic motion Simple
Handout 5: Oscillatory motion Simple harmonic motion Simple

Physics Words
Physics Words

Work and Power Notes
Work and Power Notes

... Some work is done against another force. • An archer stretches her bowstring, doing work against the elastic forces of the bow. • When the ram of a pile driver is raised, work is required to raise the ram against the force of gravity. • When you do push-ups, you do work against your own weight. ...
Physics 111 Practice Problems
Physics 111 Practice Problems

... front of it, and moving in the same direction, is a block of mass m2 = 5.0 kg moving at 3.0 m/s. A massless spring with spring constant k = 1120 N/m is attached to the near side of m2, as shown in the figure . When the blocks collide, what is the maximum compression of the spring? (Hint: At the mome ...
SIMPLE HARMONIC MOTION
SIMPLE HARMONIC MOTION

... Simple Harmonic Motion (or SHM) is the simplest form of oscillatory motion. SHM arises when force on oscillating body is directly proportional to the displacement from it's equilibrium position and at any point of motion, this force is directed towards the equilibrium position. SIMPLE HARMONIC MOTIO ...
Motion
Motion

... • When two students are pushing with unequal forces in opposite directions, a net force occurs in the direction of the larger force. ...
Springs Virtual Lab
Springs Virtual Lab

Euler Force
Euler Force

Chapter 10
Chapter 10

How do Newton`s Laws describe motion?
How do Newton`s Laws describe motion?

... What academic goals have you set? What score did you predict you will get on the next ...
ECE 3300 Portfolio 1..
ECE 3300 Portfolio 1..

... For each point in 2-D or 3-D space vectors as they are defined, will have a magnitude and direction. For example, if we have an equation for E , it will be a vector that acts a s a function of x, y and z or whatever coordinate system applies. As we “plug-in” different values of x, y, and z, a vector ...
solutions to problem set 4
solutions to problem set 4

... and the surface is 0.40, and the coefficient of kinetic friction is 0.20. (a) If no horizontal force is applied to the box and the box is at rest, how large is the friction force exerted on the box? Static friction is the relevant type for an object at rest, and would oppose a horizontal force. With ...
Chapter 10 Clickers
Chapter 10 Clickers

Learning Outcomes - Unit 1
Learning Outcomes - Unit 1

... 14. Can I calculate the resultant of two vectors in: a) a straight line b) at right angles? ...
02.Ch 9 notes
02.Ch 9 notes

... A. What was the fullback’s momentum prior to the collision? B. What was the change in the fullback’s momentum? C. What was the change in the tackle’s momentum? D. How fast the tackle moving originally? ...
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Centripetal force

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