Objective: To calculate the force needed to break an apple
... analysis will contain and discuss numbers, We do not just want to guess numbers. So, for now just hypothesize the about the method. We will be measure time of flight. We will calculate final velocity at impact. Can we then use this data to calculate the force required to break the outer surface of a ...
... analysis will contain and discuss numbers, We do not just want to guess numbers. So, for now just hypothesize the about the method. We will be measure time of flight. We will calculate final velocity at impact. Can we then use this data to calculate the force required to break the outer surface of a ...
Capacitance and Dielectrics
... Derivation of Capacitor Energy • If capacitor has charge q and I add charge dq, then I must do work dW = Vdq (Remember the definition of potential difference!) • For each dq I add, I must work harder because there is a stronger field against me. If I start with q=0 and end with q=Q, then my total w ...
... Derivation of Capacitor Energy • If capacitor has charge q and I add charge dq, then I must do work dW = Vdq (Remember the definition of potential difference!) • For each dq I add, I must work harder because there is a stronger field against me. If I start with q=0 and end with q=Q, then my total w ...
PowerPoint Presentation - Lecture 1 Electric Charge
... Motion of point charges in electric fields • When a point charge such as an electron is placed in an electric field E, it is accelerated according to Newton’s Law: a = F/m = qE/m for uniform electric fields a = F/m = mg/m = g for uniform gravitational fields If the field is uniform, we now have a p ...
... Motion of point charges in electric fields • When a point charge such as an electron is placed in an electric field E, it is accelerated according to Newton’s Law: a = F/m = qE/m for uniform electric fields a = F/m = mg/m = g for uniform gravitational fields If the field is uniform, we now have a p ...
Physics 30 review - Structured Independent Learning
... In a football game, a receiver is standing still, having just caught a pass. Before he can move, a tackler, running at a velocity of +4.5 m/s, grabs him. The tackler holds onto the receiver, and the two move off together with a velocity of +2.6 m/s. The mass of the tackler is 115 kg. Find the mass o ...
... In a football game, a receiver is standing still, having just caught a pass. Before he can move, a tackler, running at a velocity of +4.5 m/s, grabs him. The tackler holds onto the receiver, and the two move off together with a velocity of +2.6 m/s. The mass of the tackler is 115 kg. Find the mass o ...
The Calculus of Black Holes
... area of dA (represented as vectors), use dot product to find component of field that points in outward direction (only component that matters) ...
... area of dA (represented as vectors), use dot product to find component of field that points in outward direction (only component that matters) ...
Lesson 1 – Stationary Point Charges and Their Forces
... If we try to take this idea quite literally, we immediately come up with a host of objections: • How does the real particle find the energy necessary to continuously produce virtual particles, and yet not lose energy of its own? • If nothing absorbs the virtual particle, then does only the one real ...
... If we try to take this idea quite literally, we immediately come up with a host of objections: • How does the real particle find the energy necessary to continuously produce virtual particles, and yet not lose energy of its own? • If nothing absorbs the virtual particle, then does only the one real ...
ece3313notes7.
... over the surface bounded by that path. The integrand of the resulting surface integral is the curl of the vector. Given a surface S bounded by a path L, the surface can be subdivided into cells of surface area )Sk bounded by paths Lk. If we apply Ampere’s law to each cell and sum the results, the co ...
... over the surface bounded by that path. The integrand of the resulting surface integral is the curl of the vector. Given a surface S bounded by a path L, the surface can be subdivided into cells of surface area )Sk bounded by paths Lk. If we apply Ampere’s law to each cell and sum the results, the co ...
Forces & the Laws of Motion
... friction between the crate and the floor. A student moves a box of books by attaching a rope to the box and pulling with a force of 90.0 N at an angle of 30.0o. The box of books has a mass of 20.0 kg, and the coefficient of kinetic friction between the bottom of the box and the sidewalk is 0.50. Fin ...
... friction between the crate and the floor. A student moves a box of books by attaching a rope to the box and pulling with a force of 90.0 N at an angle of 30.0o. The box of books has a mass of 20.0 kg, and the coefficient of kinetic friction between the bottom of the box and the sidewalk is 0.50. Fin ...
Document
... The Maxwell continuum can be treated as a dipole density of matter. Difference between the values of the field vectors arises from differences in their sources. Both the external charges and the dipole density of the piece of matter act as sources of these vectors. The external charges contribute t ...
... The Maxwell continuum can be treated as a dipole density of matter. Difference between the values of the field vectors arises from differences in their sources. Both the external charges and the dipole density of the piece of matter act as sources of these vectors. The external charges contribute t ...