Ch. 16 Electrical Energy and Capacitance
... KE = ½ mv2 1 J = ½ (9.11x10-31kg)v2 v = 1.5 x 1015 m/s The electrons would be moving about 5 million times faster then the speed of light. ...
... KE = ½ mv2 1 J = ½ (9.11x10-31kg)v2 v = 1.5 x 1015 m/s The electrons would be moving about 5 million times faster then the speed of light. ...
Forces, Moments and Pressure
... All hydraulics systems work because the pressure is the same throughout the system. A really good example of this is a car brake system. You need to know all about this for your exams. Think about it. If you are driving a car along a motorway, you can stop it quite quickly by pushing gently on the b ...
... All hydraulics systems work because the pressure is the same throughout the system. A really good example of this is a car brake system. You need to know all about this for your exams. Think about it. If you are driving a car along a motorway, you can stop it quite quickly by pushing gently on the b ...
Chapter 11 Inductance and Magnetic Energy
... there is an electric field induced by the time-changing magnetic field that is circulating clockwise as seen from above. The force on the charges due to this electric field is thus opposite the direction the external agents are trying to spin the rings up (counterclockwise), and thus the agents have ...
... there is an electric field induced by the time-changing magnetic field that is circulating clockwise as seen from above. The force on the charges due to this electric field is thus opposite the direction the external agents are trying to spin the rings up (counterclockwise), and thus the agents have ...
Lecture 15: Refraction and Reflection
... Snell’s law holds for any polarization. It determines the direction of the transmitted fields. It does not determine the magnitude. In fact, the magnitude depends on the polarization (as we already know, since reflections are generally polarized). To determine the magnitude(s), we need the boundary ...
... Snell’s law holds for any polarization. It determines the direction of the transmitted fields. It does not determine the magnitude. In fact, the magnitude depends on the polarization (as we already know, since reflections are generally polarized). To determine the magnitude(s), we need the boundary ...
Forces and the Laws of Motion
... If the object is stationary or is moving at a constant velocity, the vectors should graphically add up to zero. If the object is accelerating, the sum of the vectors should produce a vector in the same direction as the acceleration. Writing down the sum of the forces Identify direction of every forc ...
... If the object is stationary or is moving at a constant velocity, the vectors should graphically add up to zero. If the object is accelerating, the sum of the vectors should produce a vector in the same direction as the acceleration. Writing down the sum of the forces Identify direction of every forc ...
20. Electric Charge, Force, & Field
... E// = 0 on surface of conductor. W = 0 for moving charges on / inside conductor. The entire conductor is an equipotential. Consider an isolated, spherical conductor of radius R and charge Q. Q is uniformly distributed on the surface E outside is that of a point charge Q. V(r) = k Q / R. ...
... E// = 0 on surface of conductor. W = 0 for moving charges on / inside conductor. The entire conductor is an equipotential. Consider an isolated, spherical conductor of radius R and charge Q. Q is uniformly distributed on the surface E outside is that of a point charge Q. V(r) = k Q / R. ...
Mapping Electric Fields and Equipotential Surfaces in Two
... If no current is flowing throughout a conductor, every point on the surface of the conductor is at the same potential. Such a surface is called an equipotential surface. A charged conductor is surrounded by an electric field. At a very small distance away from a conductor, there exists another surfa ...
... If no current is flowing throughout a conductor, every point on the surface of the conductor is at the same potential. Such a surface is called an equipotential surface. A charged conductor is surrounded by an electric field. At a very small distance away from a conductor, there exists another surfa ...
Physics 1212 Exam #4A (Final) Instructions:
... You may not share your calculator. The use of cell phones or any other electronic devices (besides calculators) is prohibited. All such gadgets must be turned off and put away throughout the exam. • Do not open the exam until told to begin. • You have the one entire class period to finish the exam. ...
... You may not share your calculator. The use of cell phones or any other electronic devices (besides calculators) is prohibited. All such gadgets must be turned off and put away throughout the exam. • Do not open the exam until told to begin. • You have the one entire class period to finish the exam. ...
Electricity and Magnetism I (PHY 321) Gauss`s Law problems
... Problem 3 (Fleisch Problem 1.4) What is the flux through any closed surface surrounding a charged sphere of radius a0 with volume charge density of ρ = ρ0 (r/a0 ), where r is the distance from the center of the sphere? Problem 4 (Fleisch Problem 1.5) A circular disk with surface charge density 2 × 1 ...
... Problem 3 (Fleisch Problem 1.4) What is the flux through any closed surface surrounding a charged sphere of radius a0 with volume charge density of ρ = ρ0 (r/a0 ), where r is the distance from the center of the sphere? Problem 4 (Fleisch Problem 1.5) A circular disk with surface charge density 2 × 1 ...
