CHEMICAL REACTIONS
... (s) after the formula –solid Cu(s) (g) after the formula –gas H2 (g) (l) after the formula -liquid H2O(l) (aq) after the formula - dissolved in water, an aqueous solution. CaCl2 (aq) used after a product indicates a gas (same as (g)) O2 used after a product indicates a solid (same as (s)) ...
... (s) after the formula –solid Cu(s) (g) after the formula –gas H2 (g) (l) after the formula -liquid H2O(l) (aq) after the formula - dissolved in water, an aqueous solution. CaCl2 (aq) used after a product indicates a gas (same as (g)) O2 used after a product indicates a solid (same as (s)) ...
104 Homework Packet - Rogue Community College
... According to Le Chatelier’s Principle, adding reactants (or removing products) drives the equilibrium to the __________, adding products (or removing reactants) drives the equilibrium to the __________, increasing temperature favors the ___________________ reaction, decreasing temperature favors the ...
... According to Le Chatelier’s Principle, adding reactants (or removing products) drives the equilibrium to the __________, adding products (or removing reactants) drives the equilibrium to the __________, increasing temperature favors the ___________________ reaction, decreasing temperature favors the ...
Chemical reactions alter arrangements of atoms.
... Chemical Changes Water can also undergo a chemical change. Water molecules can be broken down into hydrogen and oxygen molecules by a chemical reaction called electrolysis. When an electric current is passed through liquid water (H2O), it changes the water into two gases—hydrogen and oxygen. The mol ...
... Chemical Changes Water can also undergo a chemical change. Water molecules can be broken down into hydrogen and oxygen molecules by a chemical reaction called electrolysis. When an electric current is passed through liquid water (H2O), it changes the water into two gases—hydrogen and oxygen. The mol ...
CH 5-7 Chapter 5-7 review wkey
... 21. If you need 1.00 L of 0.125 M H2SO4, how would you prepare this solution? a) Add 950. mL of water to 50.0 mL of 3.00 M H2SO4. b) Add 500. mL of water to 500. mL of 0.500 M H2SO4. c) Add 750 mL of water to 250 mL of 0.375 M H2SO4. d) Dilute 36.0 mL of 1.25 M H2SO4 to a volume of 1.00 L. e) Dilute ...
... 21. If you need 1.00 L of 0.125 M H2SO4, how would you prepare this solution? a) Add 950. mL of water to 50.0 mL of 3.00 M H2SO4. b) Add 500. mL of water to 500. mL of 0.500 M H2SO4. c) Add 750 mL of water to 250 mL of 0.375 M H2SO4. d) Dilute 36.0 mL of 1.25 M H2SO4 to a volume of 1.00 L. e) Dilute ...
Chemistry Chapter 2 - Barnstable Academy
... a. They can be physically separated into their component elements. b. They have compositions that vary. c. They are substances. d. They have properties similar to those of their component elements. ____ 32. Which of the following materials is a substance? a. air c. stainless steel b. gasoline d. sil ...
... a. They can be physically separated into their component elements. b. They have compositions that vary. c. They are substances. d. They have properties similar to those of their component elements. ____ 32. Which of the following materials is a substance? a. air c. stainless steel b. gasoline d. sil ...
Year End Chemistry Review
... 10. Fission vs Fusion. Describe each process and explain how atoms were made. 11. Place the following numbers into or take them out of scientific notation: a) 3,000,000 b) 321,000 c) 0.00000000248 d)74.3 e) 7.419 x 104 f) 9.16 x 10-8 12. How many valence electrons are in each of the following elemen ...
... 10. Fission vs Fusion. Describe each process and explain how atoms were made. 11. Place the following numbers into or take them out of scientific notation: a) 3,000,000 b) 321,000 c) 0.00000000248 d)74.3 e) 7.419 x 104 f) 9.16 x 10-8 12. How many valence electrons are in each of the following elemen ...
Chemistry Exam Review 2
... 6) Calculate the percentage composition of vitamin C (C6H8O6). 7) Calculate the empirical formula of a compound which contains 37.5% C, 12.5% H and 50.0% O. 8) Calculate the molecular formula of a compound if its simplest formula is NaC 4H2O2 and its molar mass is 210 g/mol. 9) a) Calculate the perc ...
... 6) Calculate the percentage composition of vitamin C (C6H8O6). 7) Calculate the empirical formula of a compound which contains 37.5% C, 12.5% H and 50.0% O. 8) Calculate the molecular formula of a compound if its simplest formula is NaC 4H2O2 and its molar mass is 210 g/mol. 9) a) Calculate the perc ...
1 Q. If ΔrH is positive, what can you say about the reaction? 2 Q If
... compared to the enthalpy of the reactants? ...
... compared to the enthalpy of the reactants? ...
CHEM 101 Final (Term 151)
... D) Sugar when dissolved in water gives non-electrolytic solution. E) Solid I2 sublimed to form I2 vapor at room temperature. ...
... D) Sugar when dissolved in water gives non-electrolytic solution. E) Solid I2 sublimed to form I2 vapor at room temperature. ...
2014-15 FINAL REVIEW Nomenclature: Chemical Name Chemical
... 3. It is not safe to put aerosol canisters in a campfire, because the pressure inside the canisters gets very high and they can explode. If I have a 1.0 liter canister that holds 2 moles of gas, and the campfire temperature is 14000 C, what is the pressure inside the canister? ...
... 3. It is not safe to put aerosol canisters in a campfire, because the pressure inside the canisters gets very high and they can explode. If I have a 1.0 liter canister that holds 2 moles of gas, and the campfire temperature is 14000 C, what is the pressure inside the canister? ...
ALE 23. Balancing Redox Reactions
... photosynthesis. An understanding of redox chemistry is essential in the design of new kinds of batteries, increasing efficiency in fuel combustion, the prevention of corrosion, etc. Recall from Chem 161 (Sec. 4.5 in Silberberg), the oxidation number of an atom is the ―apparent‖ charge the atom would ...
... photosynthesis. An understanding of redox chemistry is essential in the design of new kinds of batteries, increasing efficiency in fuel combustion, the prevention of corrosion, etc. Recall from Chem 161 (Sec. 4.5 in Silberberg), the oxidation number of an atom is the ―apparent‖ charge the atom would ...
Chemistry Final Exam Review 2006-2007
... 7. What is the sign of an endothermic reaction and exothermic reaction? 8. Using the specific heat values for water and iron, which one would have the largest temperature change if they have the same mass? 9. Know how to calculate the heat released or absorbed during a physical change. a. Calculate ...
... 7. What is the sign of an endothermic reaction and exothermic reaction? 8. Using the specific heat values for water and iron, which one would have the largest temperature change if they have the same mass? 9. Know how to calculate the heat released or absorbed during a physical change. a. Calculate ...
Unit 2.2 Test Review Key
... reactants and products All types and amounts of atoms are the same in the reactants and products ...
... reactants and products All types and amounts of atoms are the same in the reactants and products ...
Lecture 20 The Redox Sequence
... In this case Red2 is the electron donor, passing electrons to Ox1 which is the electron acceptor. Thus Red2 is oxidized to Ox2 and Ox1 is reduced to Red1. The equilibrium constant for an oxidation-reduction reaction can be determined by combining the constants from Table 1 as follows for O2 with glu ...
... In this case Red2 is the electron donor, passing electrons to Ox1 which is the electron acceptor. Thus Red2 is oxidized to Ox2 and Ox1 is reduced to Red1. The equilibrium constant for an oxidation-reduction reaction can be determined by combining the constants from Table 1 as follows for O2 with glu ...
CHEM 120 WEEK 11 LECTURES (INORGANIC WEEK 2) Dr. MD
... Contains only metals, apart from boron. Boron is also the only element which does not form a stable trication (B3+) again will have too high a charge density to be stable. Why do the other elements form tri-cations (M3+ )? Soln. √ Because they have the valence electronic configuration ns2np1 and ...
... Contains only metals, apart from boron. Boron is also the only element which does not form a stable trication (B3+) again will have too high a charge density to be stable. Why do the other elements form tri-cations (M3+ )? Soln. √ Because they have the valence electronic configuration ns2np1 and ...
Unit 7 Packet
... 4. In chemical cold packs, solid ammonium chloride dissolves in water forming aqueous ammonium and chloride ions. As a result of this solvation reaction, the ...
... 4. In chemical cold packs, solid ammonium chloride dissolves in water forming aqueous ammonium and chloride ions. As a result of this solvation reaction, the ...
Balancing Redox Equations
... Oxidation Number - The charge that an atom would have if the compound in which it were found were ionic. The rules: 1) The sum of the oxidation numbers of the atoms in a molecule must be equal to the overall charge on the molecule. 2) To assign a number to a transition metal ion (not listed in the t ...
... Oxidation Number - The charge that an atom would have if the compound in which it were found were ionic. The rules: 1) The sum of the oxidation numbers of the atoms in a molecule must be equal to the overall charge on the molecule. 2) To assign a number to a transition metal ion (not listed in the t ...
Step 2
... number to each element wherever it appears in the equation. If the reaction is a redox reaction, identify the element that undergoes an increase in oxidation number and the elements the undergoes a decrease. Find the numerical values of the increase and decrease. Determine the smallest whole-number ...
... number to each element wherever it appears in the equation. If the reaction is a redox reaction, identify the element that undergoes an increase in oxidation number and the elements the undergoes a decrease. Find the numerical values of the increase and decrease. Determine the smallest whole-number ...
Water splitting
Water splitting is the general term for a chemical reaction in which water is separated into oxygen and hydrogen. Efficient and economical water splitting would be a key technology component of a hydrogen economy. Various techniques for water splitting have been issued in water splitting patents in the United States. In photosynthesis, water splitting donates electrons to power the electron transport chain in photosystem II.