Spring 2014
... 13. The equilibrium constant is equal to 5.00 at 1300 K for the reaction 2 SO2 (g) + O2 (g) W 2 SO3 (g). If initial concentrations are [SO2] = 4.0 M, [O2] = 4.0 M, and [SO3] = 4.0 M, the system is a) not at equilibrium and will shift to the right (products) to achieve an equilibrium state. b) not at ...
... 13. The equilibrium constant is equal to 5.00 at 1300 K for the reaction 2 SO2 (g) + O2 (g) W 2 SO3 (g). If initial concentrations are [SO2] = 4.0 M, [O2] = 4.0 M, and [SO3] = 4.0 M, the system is a) not at equilibrium and will shift to the right (products) to achieve an equilibrium state. b) not at ...
Exercise #5_Chpt 2
... a) What volume of 1.5M HCl solution should be present to combine totally with 0.14 moles of NaHCO 3? b) How many moles of CO2 are produced when 0.49 g of NaHCO3 combines with excess HCl? c) Calculate the mass of NaCl that results when 1.48 moles of HCl combines with excess NaHCO 3. d) What mass of N ...
... a) What volume of 1.5M HCl solution should be present to combine totally with 0.14 moles of NaHCO 3? b) How many moles of CO2 are produced when 0.49 g of NaHCO3 combines with excess HCl? c) Calculate the mass of NaCl that results when 1.48 moles of HCl combines with excess NaHCO 3. d) What mass of N ...
Lecture 11 - U of L Class Index
... Within the earth’s crust, sodium and potassium are about equally abundant; however, sea water contains about 2.8% NaCl but only about 0.8% KCl. Why this great difference, given that compounds of these elements have similar solubilities? The answer lies in the fact that potassium is an important fact ...
... Within the earth’s crust, sodium and potassium are about equally abundant; however, sea water contains about 2.8% NaCl but only about 0.8% KCl. Why this great difference, given that compounds of these elements have similar solubilities? The answer lies in the fact that potassium is an important fact ...
Review - cloudfront.net
... The amount of heat transferred from an object depends on which of the following? a. the specific heat of the object c. the mass of the object b. the initial temperature of the object d. all of the above At what stage of a reaction do atoms have the highest energy? a. reactant stage b. product stage ...
... The amount of heat transferred from an object depends on which of the following? a. the specific heat of the object c. the mass of the object b. the initial temperature of the object d. all of the above At what stage of a reaction do atoms have the highest energy? a. reactant stage b. product stage ...
CHEMISTRY 110 LECTURE
... 6. Iron (III) oxide can react with aluminum metal to produce aluminum oxide and iron metal (hint: this is the chemical rxn!!) This is called the thermit reaction and it produces so much heat that it can be used for incendiary bombs and for welding. How many grams of aluminum oxide will be produced b ...
... 6. Iron (III) oxide can react with aluminum metal to produce aluminum oxide and iron metal (hint: this is the chemical rxn!!) This is called the thermit reaction and it produces so much heat that it can be used for incendiary bombs and for welding. How many grams of aluminum oxide will be produced b ...
Classifying Reactions: A good summary
... when a portion substance is oxidized while the rest is reduced. The same chemical substance undergoes both oxidation and reduction. NO2 and H2O2 are classic chemicals that have this ability. Example: 3NO2(g) + H2O ...
... when a portion substance is oxidized while the rest is reduced. The same chemical substance undergoes both oxidation and reduction. NO2 and H2O2 are classic chemicals that have this ability. Example: 3NO2(g) + H2O ...
FORMULA WRITNG
... (a) propane gas (C3H8), which is used for heating, is burned with insufficient oxygen, the flame is yellow and smoky because the products are elemental carbon and water vapor. (b) Potassium chloride is synthesized from its elements (c) Nitrogen monoxide plus oxygen gas gives nitrogen dioxide gas (d) ...
... (a) propane gas (C3H8), which is used for heating, is burned with insufficient oxygen, the flame is yellow and smoky because the products are elemental carbon and water vapor. (b) Potassium chloride is synthesized from its elements (c) Nitrogen monoxide plus oxygen gas gives nitrogen dioxide gas (d) ...
model paper-1 - WordPress.com
... b) Which out of NH3 and NF3 has higher dipole moment and why? 3M 15. a) Under what conditions, real gases show ideal gas behavior? On a ship sailing in Pacific Ocean where temperature is 26.40C, a balloon is filled with 1.4L air. What will be the volume of the balloon when the ship reaches Indian Oc ...
... b) Which out of NH3 and NF3 has higher dipole moment and why? 3M 15. a) Under what conditions, real gases show ideal gas behavior? On a ship sailing in Pacific Ocean where temperature is 26.40C, a balloon is filled with 1.4L air. What will be the volume of the balloon when the ship reaches Indian Oc ...
Document
... The Shape of the Molecules Valence Shell Electron Pair Repulsion (VSEPR) theory is the model mostly used to predict molecular shape. Electron pairs on the central atom repel one another. The two dimensional dot structure of methane, CH4. gives the angles between electron pairs of 90o. But the dot s ...
... The Shape of the Molecules Valence Shell Electron Pair Repulsion (VSEPR) theory is the model mostly used to predict molecular shape. Electron pairs on the central atom repel one another. The two dimensional dot structure of methane, CH4. gives the angles between electron pairs of 90o. But the dot s ...
Chemistry Final Exam Practice Test
... a) It is a molecular formula b) It is a formula unit c) It gives information about molecular structure d) It is the formula of an ionic compound e) It represents a molecule made of 1 carbon atom, 2 hydrogen atoms, and 6 oxygen atoms. ...
... a) It is a molecular formula b) It is a formula unit c) It gives information about molecular structure d) It is the formula of an ionic compound e) It represents a molecule made of 1 carbon atom, 2 hydrogen atoms, and 6 oxygen atoms. ...
Chemistry Review 1 Answer Key
... condition was mentioned in the first sentence of the passage. Therefore, the condition not mentioned is high temperature. [1 point] 'see explanation below' 29. Base your answer on the information below. Carbon and oxygen are examples of elements that exist in more than one form in the same phase. Gr ...
... condition was mentioned in the first sentence of the passage. Therefore, the condition not mentioned is high temperature. [1 point] 'see explanation below' 29. Base your answer on the information below. Carbon and oxygen are examples of elements that exist in more than one form in the same phase. Gr ...
Chemistry - NIC Karnataka
... General introduction to p– block elements-electronic configuration, oxidation states, inert pair effect, anomalous behavior of first member of each group. Group 13 elements: General introduction, electronic configuration, occurrence , variation of atomic radii, ionization enthalpy, electronegativity ...
... General introduction to p– block elements-electronic configuration, oxidation states, inert pair effect, anomalous behavior of first member of each group. Group 13 elements: General introduction, electronic configuration, occurrence , variation of atomic radii, ionization enthalpy, electronegativity ...
g - nhscrazy4chem
... The above equation means that the ΔHf for 1 mole of hydrogen = 218 kJ Using bond enthalpies it is possible to explain why gas phase reactions are endothermic. Generally, a reaction is expected to be endothermic if: ...
... The above equation means that the ΔHf for 1 mole of hydrogen = 218 kJ Using bond enthalpies it is possible to explain why gas phase reactions are endothermic. Generally, a reaction is expected to be endothermic if: ...
Oxidation-Reduction and Electrochemistry
... body, and is its positive extremity; the combustible bodies, metals, alkalies, and bases are evolved there, and it is in contact with the negative electrode. Many bodies are decomposed directly by the electric current, their elements being set free; these I propose to call electrolytes.... Final ...
... body, and is its positive extremity; the combustible bodies, metals, alkalies, and bases are evolved there, and it is in contact with the negative electrode. Many bodies are decomposed directly by the electric current, their elements being set free; these I propose to call electrolytes.... Final ...
WELCOME TO AP CHEMISTRY
... Know how to use the solubility chart and activity series for both metals and halogens. Review metrics, scientific notation and dimensional analysis. Success in AP Chemistry depends on two things: ability and motivation. Both components are necessary. You will be required to solve hundreds of problem ...
... Know how to use the solubility chart and activity series for both metals and halogens. Review metrics, scientific notation and dimensional analysis. Success in AP Chemistry depends on two things: ability and motivation. Both components are necessary. You will be required to solve hundreds of problem ...
Describing Chemical Reactions
... reaction, the total mass of the reactants must equal the total mass of the products. In an open system, matter can enter from or escape to the surroundings. A match burning in the air is an example of an open system. You cannot measure the mass of all the reactants and products in an open system. A ...
... reaction, the total mass of the reactants must equal the total mass of the products. In an open system, matter can enter from or escape to the surroundings. A match burning in the air is an example of an open system. You cannot measure the mass of all the reactants and products in an open system. A ...
Water splitting
Water splitting is the general term for a chemical reaction in which water is separated into oxygen and hydrogen. Efficient and economical water splitting would be a key technology component of a hydrogen economy. Various techniques for water splitting have been issued in water splitting patents in the United States. In photosynthesis, water splitting donates electrons to power the electron transport chain in photosystem II.