Midterm Solutions
... (a) Correctness. No. The correctness of a sorting algorithm means that the resulting array is in ascending order, and it contains exactly the same elements that you began with. Neither property is satisfied here because of a catastrophic off-by-one error that causes L[lo-1] and H[hi-1] to be lost. ( ...
... (a) Correctness. No. The correctness of a sorting algorithm means that the resulting array is in ascending order, and it contains exactly the same elements that you began with. Neither property is satisfied here because of a catastrophic off-by-one error that causes L[lo-1] and H[hi-1] to be lost. ( ...
chap11
... – If both factors are positive (>), then make left rotation at x – If both negative (<), make right rotation at x ...
... – If both factors are positive (>), then make left rotation at x – If both negative (<), make right rotation at x ...
Ch 10 - Personal.kent.edu
... §- Traversing Through a Tree - There are six simple recursive algorithms for tree traversal. - The most commonly used ones are: 1)inorder (LNR) 2)postorder (LRN) 3)preorder (NLR). - Another technique is to move left to right from level to level. §- This algorithm is iterative, and its implementation ...
... §- Traversing Through a Tree - There are six simple recursive algorithms for tree traversal. - The most commonly used ones are: 1)inorder (LNR) 2)postorder (LRN) 3)preorder (NLR). - Another technique is to move left to right from level to level. §- This algorithm is iterative, and its implementation ...
file_organize
... 1. Each internal node is of the form
where q 1 p and each Pi is a tree pointer.
2. Within each internal node, K1 < K2 < ...
... 1. Each internal node is of the form
Day21
... there is a form of a tree that maintains both the sorted property and the balanced property. They are called AVL trees but they are a lot more work! ...
... there is a form of a tree that maintains both the sorted property and the balanced property. They are called AVL trees but they are a lot more work! ...
Index Structures for Files
... level of every other node is one more than that of its parent • A subtree of a node consists of the node and all of its descendant nodes (its children, grandchildren, etc.) • Each node of a tree used as an indexing structure can contain data and several pointers ...
... level of every other node is one more than that of its parent • A subtree of a node consists of the node and all of its descendant nodes (its children, grandchildren, etc.) • Each node of a tree used as an indexing structure can contain data and several pointers ...
ppt - Dave Reed`s
... e.g., to display all the values in a (nonempty) binary tree, divide into 1. displaying the root 2. (recursively) displaying all the values in the left subtree 3. (recursively) displaying all the values in the right subtree ...
... e.g., to display all the values in a (nonempty) binary tree, divide into 1. displaying the root 2. (recursively) displaying all the values in the left subtree 3. (recursively) displaying all the values in the right subtree ...
Binary Trees - jprodriguez.net
... • Visit order: left subtree, right subtree, node • Must track for the node whether the left and right subtrees have been visited – Solution: Save a pointer to the node, and also save an integer value of 1 before moving to the left subtree and value of 2 before moving to the right subtree – When the ...
... • Visit order: left subtree, right subtree, node • Must track for the node whether the left and right subtrees have been visited – Solution: Save a pointer to the node, and also save an integer value of 1 before moving to the left subtree and value of 2 before moving to the right subtree – When the ...
recursively
... e.g., to display all the values in a (nonempty) binary tree, divide into 1. displaying the root 2. (recursively) displaying all the values in the left subtree 3. (recursively) displaying all the values in the right subtree ...
... e.g., to display all the values in a (nonempty) binary tree, divide into 1. displaying the root 2. (recursively) displaying all the values in the left subtree 3. (recursively) displaying all the values in the right subtree ...
Solution - GitHub Pages
... 3.26 Describe in a few sentences how to implement three stacks in one array. Ans Three stacks can be implemented by having one grow from the bottom up, another from the top down and a third somewhere in the middle growing in some (arbitrary) direction. If the third stack collides with either of the ...
... 3.26 Describe in a few sentences how to implement three stacks in one array. Ans Three stacks can be implemented by having one grow from the bottom up, another from the top down and a third somewhere in the middle growing in some (arbitrary) direction. If the third stack collides with either of the ...
CSE143 Lecture 23: Priority Queues and HuffmanTree
... • list : store customers/jobs in a list; remove min/max by searching (O(N)) – problem: expensive to search • sorted list : store in sorted list; binary search it in O(log N) time – problem: expensive to add/remove • binary search tree : store in BST, search in O(log N) time for min element – problem ...
... • list : store customers/jobs in a list; remove min/max by searching (O(N)) – problem: expensive to search • sorted list : store in sorted list; binary search it in O(log N) time – problem: expensive to add/remove • binary search tree : store in BST, search in O(log N) time for min element – problem ...
Stacks, Queues, and Trees
... Each node (except the root) gets charged twice: once for its own call and once for its parent’s call. Therefore, traversal time is O(n). ...
... Each node (except the root) gets charged twice: once for its own call and once for its parent’s call. Therefore, traversal time is O(n). ...
Chapter 20
... • Visit order: left subtree, right subtree, node • We must indicate to the node whether the left and right subtrees have been visited − Solution: other than saving a pointer to the node, save an integer value of 1 before moving to the left subtree and value of 2 before moving to the right subtree − ...
... • Visit order: left subtree, right subtree, node • We must indicate to the node whether the left and right subtrees have been visited − Solution: other than saving a pointer to the node, save an integer value of 1 before moving to the left subtree and value of 2 before moving to the right subtree − ...
Binary search tree
In computer science, binary search trees (BST), sometimes called ordered or sorted binary trees, are a particular type of containers: data structures that store ""items"" (such as numbers, names and etc.) in memory. They allow fast lookup, addition and removal of items, and can be used to implement either dynamic sets of items, or lookup tables that allow finding an item by its key (e.g., finding the phone number of a person by name).Binary search trees keep their keys in sorted order, so that lookup and other operations can use the principle of binary search: when looking for a key in a tree (or a place to insert a new key), they traverse the tree from root to leaf, making comparisons to keys stored in the nodes of the tree and deciding, based on the comparison, to continue searching in the left or right subtrees. On average, this means that each comparison allows the operations to skip about half of the tree, so that each lookup, insertion or deletion takes time proportional to the logarithm of the number of items stored in the tree. This is much better than the linear time required to find items by key in an (unsorted) array, but slower than the corresponding operations on hash tables.They are a special case of the more general B-tree with order equal to two.