NumberSystems
... • Recall that the spacing between numbers in [Be, Be+1] is B1-p+e = B1-pBe = εBe • If |x| is in [Be, Be+1], then Be <= |x| <= Be+1 => spacing = εBe <= ε|x| <= εBe+1 => εBe-1 <= ε|x|/B <= εBe = spacing => ε|x|/B <= spacing at x <= ε|x| • The last line is the fact to remember – We’ll use it in designi ...
... • Recall that the spacing between numbers in [Be, Be+1] is B1-p+e = B1-pBe = εBe • If |x| is in [Be, Be+1], then Be <= |x| <= Be+1 => spacing = εBe <= ε|x| <= εBe+1 => εBe-1 <= ε|x|/B <= εBe = spacing => ε|x|/B <= spacing at x <= ε|x| • The last line is the fact to remember – We’ll use it in designi ...
Rational Numbers - Abstractmath.org
... Suppose we have a line segment L that is 5/8 of a unit long. Then we can take a line segment M that is 1 unit long and divide it into exactly 8 segments of 1/8 unit each, and we can divide L into exactly 5 segments of the same length. That is because the ratio of L to M is 5:8. Remarkably, we cannot ...
... Suppose we have a line segment L that is 5/8 of a unit long. Then we can take a line segment M that is 1 unit long and divide it into exactly 8 segments of 1/8 unit each, and we can divide L into exactly 5 segments of the same length. That is because the ratio of L to M is 5:8. Remarkably, we cannot ...
