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Solution
Solution

2015-2016 Mrs. Smart 11/10/2015 - 12/04/2015 Class View Page 1
2015-2016 Mrs. Smart 11/10/2015 - 12/04/2015 Class View Page 1

ALGEBRAIC NUMBER THEORY 1. Algebraic Integers Let A be a
ALGEBRAIC NUMBER THEORY 1. Algebraic Integers Let A be a

x + - Big Ideas Math
x + - Big Ideas Math

Full text
Full text

english, pdf
english, pdf

On repdigits as product of consecutive Fibonacci
On repdigits as product of consecutive Fibonacci

... where F0 = 0 and F1 = 1. These numbers are well-known for possessing amazing properties. In 1963, the Fibonacci Association was created to provide an opportunity to share ideas about these intriguing numbers and their applications. We remark that, in 2003, Bugeaud et al. [2] proved that the only per ...
Chebyshev`s conjecture and the prime number race
Chebyshev`s conjecture and the prime number race

prime numbers and encryption
prime numbers and encryption

a+b
a+b

Acta Academiae Paedagogicae Agriensis, Sectio Mathematicae 31
Acta Academiae Paedagogicae Agriensis, Sectio Mathematicae 31

... 17 once |x| ≥ 240. The method presented in [8] is elementary, and the computations were done using congruences with respect to small moduli. The purpose of this note is two fold. First of all, we improve the lower bound from [8] by showing that P (x2 + 1) ≥ 101 once |x| ≥ 24208145. Secondly, our met ...
Modular Arithmetic
Modular Arithmetic

primality proving - American Mathematical Society
primality proving - American Mathematical Society

Integer Functions - Books in the Mathematical Sciences
Integer Functions - Books in the Mathematical Sciences

Solutions to exam 1
Solutions to exam 1

Slides
Slides

Solutions to Problems
Solutions to Problems

Why Is the 3X + 1 Problem Hard? - Department of Mathematics, CCNY
Why Is the 3X + 1 Problem Hard? - Department of Mathematics, CCNY

Full text
Full text

Modular forms and Diophantine questions
Modular forms and Diophantine questions

... assertion that is true experimentally may have one or more counterexamples that happen to be very large. In fact, assertions that realize this possibility are not hard to find in number theory. As Fermat himself knew, the first solution to x2 −109y 2 = 1 in positive integers x and y is given by x = ...
lesson-4modular-arithmetric1
lesson-4modular-arithmetric1

4 slides/page
4 slides/page

19 4|( + 1)
19 4|( + 1)

Sample pages 1 PDF
Sample pages 1 PDF

... for all real x ≥ 2, ...
Cryptography and Network Security Chapter 4
Cryptography and Network Security Chapter 4

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Quadratic reciprocity

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