
Application to Stirling numbers
... Example: m=1, P=[0,1], Q=(-1,0). nP = [0,n]; nP Z = {0,1,...,n-1,n} (-n)Q=(n,0); (-n)Q Z = {n+1,n+2,...,-2,-1}. More generally: Suppose P is d dimensional, with d = m. Then b(n) = (-1)^d sum_{x in (-n)Q} a(x), where Q now denotes the relative interior of P (that is, the interior of P relative ...
... Example: m=1, P=[0,1], Q=(-1,0). nP = [0,n]; nP Z = {0,1,...,n-1,n} (-n)Q=(n,0); (-n)Q Z = {n+1,n+2,...,-2,-1}. More generally: Suppose P is d dimensional, with d = m. Then b(n) = (-1)^d sum_{x in (-n)Q} a(x), where Q now denotes the relative interior of P (that is, the interior of P relative ...
5. p-adic Numbers 5.1. Motivating examples. We all know that √2 is
... P∞ features, such as the fact that every p-adic triangle is isosceles. Another one is: a series n=1 an with terms an ∈ Qp converges if and only if the terms tend to zero, i.e. limn→∞ an = 0. We will prove a special case of this in the next proposition. Rather than continuing with this analytic theor ...
... P∞ features, such as the fact that every p-adic triangle is isosceles. Another one is: a series n=1 an with terms an ∈ Qp converges if and only if the terms tend to zero, i.e. limn→∞ an = 0. We will prove a special case of this in the next proposition. Rather than continuing with this analytic theor ...