Powers and Roots2
... Multiply the problem as you would multiply any fractions. Also, the FOIL method of multiplying binomials will come in handy. 20 + 4(SQRT(2)) + 5(SQRT(2)) + (SQRT(2))2 ----------------------------------------25 + 5(SQRT(2)) - 5(SQRT(2)) - (SQRT(2))2 Perform any indicated operations. 20 + 4(SQRT(2)) + ...
... Multiply the problem as you would multiply any fractions. Also, the FOIL method of multiplying binomials will come in handy. 20 + 4(SQRT(2)) + 5(SQRT(2)) + (SQRT(2))2 ----------------------------------------25 + 5(SQRT(2)) - 5(SQRT(2)) - (SQRT(2))2 Perform any indicated operations. 20 + 4(SQRT(2)) + ...
Subtraction of Fractions with equal denominators
... a fraction can have many different appearances, these are called equivalent fractions In the following picture we have ½ of a cake because the whole cake is divided into two congruent parts and we have only one of those parts. But if we cut the cake into smaller congruent pieces, we can see that ...
... a fraction can have many different appearances, these are called equivalent fractions In the following picture we have ½ of a cake because the whole cake is divided into two congruent parts and we have only one of those parts. But if we cut the cake into smaller congruent pieces, we can see that ...
Intermediate Math Circles November 25, 2009 Diophantine
... The next two are harder, but if you can, find a rule for. . . (6) When a number is divisible by 8. (7) When a number is divisible by 7. (Hint: the rule has something to do with breaking the number down into the ones digit, and then the number made up of all the other digits: 1031 = 103 and 1: Now, c ...
... The next two are harder, but if you can, find a rule for. . . (6) When a number is divisible by 8. (7) When a number is divisible by 7. (Hint: the rule has something to do with breaking the number down into the ones digit, and then the number made up of all the other digits: 1031 = 103 and 1: Now, c ...
