a) - BrainMass
... So, GCD(135, 60)=15 c) Find the greatest common divisor of 1,234,567 and 7,654,321. Use method 1. GCD(1234567 ; 7654321) =GCD(1234567 ; |7654321-1234567|) =GCD(1234567 ; 6419754) =GCD(1234567 ; |6419754-1234567|) =GCD(1234567 ; 5185187) =GCD(1234567 ; 3950620) =GCD(1234567 ; 2716053) =GCD(1234567 ; ...
... So, GCD(135, 60)=15 c) Find the greatest common divisor of 1,234,567 and 7,654,321. Use method 1. GCD(1234567 ; 7654321) =GCD(1234567 ; |7654321-1234567|) =GCD(1234567 ; 6419754) =GCD(1234567 ; |6419754-1234567|) =GCD(1234567 ; 5185187) =GCD(1234567 ; 3950620) =GCD(1234567 ; 2716053) =GCD(1234567 ; ...
Ready Set Math!
... Ready, Set, Math! The following is a comprehensive list of the math skills students learn in each grade. The skills are organized into categories: As you read the activities in the plan, keep in mind the specifics skills your students need to practice and master in the different grade levels you wor ...
... Ready, Set, Math! The following is a comprehensive list of the math skills students learn in each grade. The skills are organized into categories: As you read the activities in the plan, keep in mind the specifics skills your students need to practice and master in the different grade levels you wor ...
THE MILLER–RABIN TEST 1. Introduction
... In all three cases, 1 and n − 1 are nonwitnesses (note n is odd). Another common feature is that all three types of nonwitnesses are relatively prime to n. It is easy to see that the Fermat nonwitnesses and Euler nonwitnesses for n each form a group under multiplication mod n. If n is composite then ...
... In all three cases, 1 and n − 1 are nonwitnesses (note n is odd). Another common feature is that all three types of nonwitnesses are relatively prime to n. It is easy to see that the Fermat nonwitnesses and Euler nonwitnesses for n each form a group under multiplication mod n. If n is composite then ...
Homework 3 Solutions
... 31957 is 1 mod 4. (Remark 1: The “only if” version—that there would be no solution if the Legendre symbol were −1—is true, but we don’t need it here.) (Remark 2: If we were looking for roots in the real numbers, instead of modulo a prime, we’d use the quadratic formula and find that the discriminant ...
... 31957 is 1 mod 4. (Remark 1: The “only if” version—that there would be no solution if the Legendre symbol were −1—is true, but we don’t need it here.) (Remark 2: If we were looking for roots in the real numbers, instead of modulo a prime, we’d use the quadratic formula and find that the discriminant ...
2005 Exam
... 20. A 20-foot by 30-foot rectangular barn sits in the middle of a flat, open field. The farmer wants to tether a goat to the barn using a chain 50 feet long. The goat cannot go under, into, or through the barn. If the farmer wishes to provide the goat with the maximum possible grazing area, then th ...
... 20. A 20-foot by 30-foot rectangular barn sits in the middle of a flat, open field. The farmer wants to tether a goat to the barn using a chain 50 feet long. The goat cannot go under, into, or through the barn. If the farmer wishes to provide the goat with the maximum possible grazing area, then th ...
