How a computer stores numbers
... How about fractions whose denominators are not powers of 2, such as 2/3? We could start off by noting that 1/2 ≤ 2/3 < 1, so the expression starts off with ‘0.1’; then subtract 2/3 − 1/2 = 1/6; 1/8 < 1/6 < 1/4 so it continues ‘0.101’; etc. But this involves sooner or later a lot of large denominato ...
... How about fractions whose denominators are not powers of 2, such as 2/3? We could start off by noting that 1/2 ≤ 2/3 < 1, so the expression starts off with ‘0.1’; then subtract 2/3 − 1/2 = 1/6; 1/8 < 1/6 < 1/4 so it continues ‘0.101’; etc. But this involves sooner or later a lot of large denominato ...
High Sc ho ol
... 4. On a certain test, the average score for the women in the class is 83, while the average score for the men in the class is 71. If the average score of all the students in the class is 80, then what percentage of the students are women? (a) 60% ...
... 4. On a certain test, the average score for the women in the class is 83, while the average score for the men in the class is 71. If the average score of all the students in the class is 80, then what percentage of the students are women? (a) 60% ...
Document
... 5. (6) Let ℕ be the set of nonnegative integers. For each of the following sentences in firstorder logic, state whether the sentence is valid, is satisfiable (but not valid), or is unsatisfiable. (1) x ℕ (y ℕ (y < x)). ...
... 5. (6) Let ℕ be the set of nonnegative integers. For each of the following sentences in firstorder logic, state whether the sentence is valid, is satisfiable (but not valid), or is unsatisfiable. (1) x ℕ (y ℕ (y < x)). ...
Math 17 Winter 2015 Notes from January 5 In class on Monday
... of a. If p were a prime factor of b, then it would be a prime factor of db2 , and therefore also a prime factor of a. But we wrote our fraction in lowest terms, so p cannot be a prime factor of both a and b. This means that p could not have been a prime factor of b after all. Therefore, b has no pri ...
... of a. If p were a prime factor of b, then it would be a prime factor of db2 , and therefore also a prime factor of a. But we wrote our fraction in lowest terms, so p cannot be a prime factor of both a and b. This means that p could not have been a prime factor of b after all. Therefore, b has no pri ...
Factors, Fractions and Exponents
... • E.g., Simplify 6(4 + 3)2. First, do the operation within the parenthesis. We get 6(7)2. Second, do the exponent. Since 7 x 7 = 49, we get 6(49). Now multiply 6(49) = 294. – BTW: I multiplied 6(49) in my head by using the distributive property. 6(50 – 1) = 6(50) – 6(1) = 300 – 6 = 294. ...
... • E.g., Simplify 6(4 + 3)2. First, do the operation within the parenthesis. We get 6(7)2. Second, do the exponent. Since 7 x 7 = 49, we get 6(49). Now multiply 6(49) = 294. – BTW: I multiplied 6(49) in my head by using the distributive property. 6(50 – 1) = 6(50) – 6(1) = 300 – 6 = 294. ...
