Around the Littlewood conjecture in Diophantine approximation
... The assumption of Theorem 20 can be restated as follows. To an irrational real number α := [a0 ; a1 , a2 , . . .] we associate the set Adh(α) := {[0; am , am+1 , . . .] : m ≥ 1}, which is the closure of the set composed of the iterates of {α} under the Gauss transformation. Then, Theorem 20 asserts ...
... The assumption of Theorem 20 can be restated as follows. To an irrational real number α := [a0 ; a1 , a2 , . . .] we associate the set Adh(α) := {[0; am , am+1 , . . .] : m ≥ 1}, which is the closure of the set composed of the iterates of {α} under the Gauss transformation. Then, Theorem 20 asserts ...
Partition of a Set which Contains an Infinite Arithmetic (Respectively
... contains an infinite number of triplets such that each triplet is an arithmetic (respectively geometric) progression. Introduction. First, in this article we build sets which have the following property: for any partition in two subsets, at least one of these subsets contains at least three elements ...
... contains an infinite number of triplets such that each triplet is an arithmetic (respectively geometric) progression. Introduction. First, in this article we build sets which have the following property: for any partition in two subsets, at least one of these subsets contains at least three elements ...
Open Sentences A mathematical statement consisting of two
... Substitute each element in the replacement set for the specified variable into the inequality and simplify. Those elements that produce a true statement are members of the solution set. Given: replacement set {20, 21, 22, 23} Find solution set for z + 11 > 32 ...
... Substitute each element in the replacement set for the specified variable into the inequality and simplify. Those elements that produce a true statement are members of the solution set. Given: replacement set {20, 21, 22, 23} Find solution set for z + 11 > 32 ...
If 3x is one factor of , what is the other factor
... x2 term must be positive. Move all terms to the side where + x2 is. If you are given -x2, subtract it over to the other side of the equation to make it positive. ...
... x2 term must be positive. Move all terms to the side where + x2 is. If you are given -x2, subtract it over to the other side of the equation to make it positive. ...
