![Quantum Computing Lecture 1 Bits and Qubits What is Quantum](http://s1.studyres.com/store/data/003637237_1-3c368f434289ed0c5adb8a85bb940e24-300x300.png)
April 16, 1998 - StealthSkater
... interaction Hamiltonian. In particular, there does not appear to be any meaning to what Larry Crowell describes as "self-measurement" in terms of the von Neumann theory. Therefore, any appeal to a Cantor diagonal argument for a strange loop in a quantum Turing machine has no context until precisely ...
... interaction Hamiltonian. In particular, there does not appear to be any meaning to what Larry Crowell describes as "self-measurement" in terms of the von Neumann theory. Therefore, any appeal to a Cantor diagonal argument for a strange loop in a quantum Turing machine has no context until precisely ...
Finite Quantum Measure Spaces
... D(A, B) = ν(A)ν(B). The corresponding quantum measure is therefore µ(A) = D(A, A) = |ν(A)|2 . If A, B ⊂ X are disjoint, then computing the measure of A ∪ B will show that µ is not grade-1 additive: µ(A ∪ B) = |ν(A ∪ B)|2 = |ν(A) + ν(B)|2 = |ν(A)|2 + |ν(B)|2 + 2Re[ν(A)ν(B)] = µ(A) + µ(B) + 2Re[D(A, B ...
... D(A, B) = ν(A)ν(B). The corresponding quantum measure is therefore µ(A) = D(A, A) = |ν(A)|2 . If A, B ⊂ X are disjoint, then computing the measure of A ∪ B will show that µ is not grade-1 additive: µ(A ∪ B) = |ν(A ∪ B)|2 = |ν(A) + ν(B)|2 = |ν(A)|2 + |ν(B)|2 + 2Re[ν(A)ν(B)] = µ(A) + µ(B) + 2Re[D(A, B ...