2.6 Complex Numbers
... In the past section, we have gone to considerable effort to approximate functions that have all derivatives by polynomials, the latter being particularly wellbehaved and well-understood. In fact, in more sophisticated situations than we have studied in this course, but which you will see in later co ...
... In the past section, we have gone to considerable effort to approximate functions that have all derivatives by polynomials, the latter being particularly wellbehaved and well-understood. In fact, in more sophisticated situations than we have studied in this course, but which you will see in later co ...
Complex Numbers: Basic Results The set of complex numbers (C) is
... The cosine and sine functions both have period 2π. It then follows from (E) that eiθ also has period 2π: ei(θ+2π) = eiθ for any θ ∈ R. This can also be seen by examining the next figure. More generally, ei(θ+2kπ) = eiθ for any θ ∈ R and any integer k. Figure 4: The Unit Circle Im z i it ............ ...
... The cosine and sine functions both have period 2π. It then follows from (E) that eiθ also has period 2π: ei(θ+2π) = eiθ for any θ ∈ R. This can also be seen by examining the next figure. More generally, ei(θ+2kπ) = eiθ for any θ ∈ R and any integer k. Figure 4: The Unit Circle Im z i it ............ ...
Lecture Notes for Section 1.4 (Complex Numbers)
... Big Idea: .Calling the square root of negative one “i” allows us to state the solution of many algebra equations that would otherwise be unsolvable with real numbers. Big Skill: You should be able to perform arithmetic (add, subtract, multiply, and divide) with complex numbers. A. Identifying and Si ...
... Big Idea: .Calling the square root of negative one “i” allows us to state the solution of many algebra equations that would otherwise be unsolvable with real numbers. Big Skill: You should be able to perform arithmetic (add, subtract, multiply, and divide) with complex numbers. A. Identifying and Si ...
Topic: Properties of Exponents Definition: Exponents represent
... Since the base of each exponential is 2, we can apply the addition property. 24 2−6 23 becomes 24−6+3 = 21 = 2. This is far easier than finding the value of each factor and then multiplying. 2. Write x−3 x8 x9 using a single exponent. Since the base of each exponential is x, we can apply the additio ...
... Since the base of each exponential is 2, we can apply the addition property. 24 2−6 23 becomes 24−6+3 = 21 = 2. This is far easier than finding the value of each factor and then multiplying. 2. Write x−3 x8 x9 using a single exponent. Since the base of each exponential is x, we can apply the additio ...
