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Section 1.3 Linear Equations in Two Variables

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... a unique solution; this requires that a 6= 0. Also, if a < 0, then x = −(−a)1/4 is a choice of x for which the equation has no solution. If a > 0, then for every x ∈ R we can solve the equation for y to obtain y = −f racxx4 + a. This computes a unique value for y that makes the equation true. Thus t ...
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