
2008 Exam with Solution
... 2. The sliders A and B are connected by a light rigid bar of length l = 0.5m and move with negligible friction in the horizontal slots shown. For the position where x A = 0.4m , the velocity of A is v A = 0.9m / s to the right. Determine the acceleration of each slider and the force in the bar at th ...
... 2. The sliders A and B are connected by a light rigid bar of length l = 0.5m and move with negligible friction in the horizontal slots shown. For the position where x A = 0.4m , the velocity of A is v A = 0.9m / s to the right. Determine the acceleration of each slider and the force in the bar at th ...
Chapter 10 Dynamics of Rotational Motion
... and thus one might think of potential energy coming from a point particle with mass M located at the body’s center of mass. Example 10.4. You make a primitive yo-yo by wrapping a massless string around a solid cylinder with mass M and radius R. You hold the free end of the string stationary and rele ...
... and thus one might think of potential energy coming from a point particle with mass M located at the body’s center of mass. Example 10.4. You make a primitive yo-yo by wrapping a massless string around a solid cylinder with mass M and radius R. You hold the free end of the string stationary and rele ...
Pdf - Text of NPTEL IIT Video Lectures
... So, that will be given as half I p and theta dot square, because it is oscillating with theta and velocity is theta dot. So, we can see that both the linear and rotational kinetic energy is there in this. And now we are having a displacement or the extension of the spring because of this displaceme ...
... So, that will be given as half I p and theta dot square, because it is oscillating with theta and velocity is theta dot. So, we can see that both the linear and rotational kinetic energy is there in this. And now we are having a displacement or the extension of the spring because of this displaceme ...