Chapter 8
... A rigid body is an object or a system of particles in which the distances between particles are fixed (remain constant). In other words, a rigid body must be solid (but not all solid bodies are rigid). ...
... A rigid body is an object or a system of particles in which the distances between particles are fixed (remain constant). In other words, a rigid body must be solid (but not all solid bodies are rigid). ...
Chapter 8
... point 2.0 m from the axis of rotation. What is the new angular speed when the man walks to a point 1.0 m from the center? Assume that the merry-go-round is a solid 25 kg cylinder with a radius of 2.0 m. ...
... point 2.0 m from the axis of rotation. What is the new angular speed when the man walks to a point 1.0 m from the center? Assume that the merry-go-round is a solid 25 kg cylinder with a radius of 2.0 m. ...
Physics 106P: Lecture 1 Notes
... Example 7.1: A car w/ mass 1200 kg is driving north at 30 m/s, and turns east driving 13.6 m/s. What is the magnitude of the car’s change in momentum? pinitial = m vinitial = (1200 Kg) x 30 m/s = 36000 kg m/s North pfinal = m vfinal = (1200 Kg) x 13.6 m/s = 16320 kg m/s East ...
... Example 7.1: A car w/ mass 1200 kg is driving north at 30 m/s, and turns east driving 13.6 m/s. What is the magnitude of the car’s change in momentum? pinitial = m vinitial = (1200 Kg) x 30 m/s = 36000 kg m/s North pfinal = m vfinal = (1200 Kg) x 13.6 m/s = 16320 kg m/s East ...
11. Rotation Translational Motion
... H Will define a set of quantities to describe rotational motion similar to position, displacement, velocity, and acceleration used to describe translational motion. Angular Position (θ ...
... H Will define a set of quantities to describe rotational motion similar to position, displacement, velocity, and acceleration used to describe translational motion. Angular Position (θ ...
Notes with Impulse
... If you run into a brick wall with momentum x, the contact time is short and the force large (ouch!) If you run into a wall of pillows with momentum x, the contact time is long and force small (pain is minimized) ...
... If you run into a brick wall with momentum x, the contact time is short and the force large (ouch!) If you run into a wall of pillows with momentum x, the contact time is long and force small (pain is minimized) ...
L3 ROTATIONAL MOTION
... This gravitational potential energy is changed into linear kinetic energy of the mass and of the roller plus rotational kinetic energy of the roller; Ep = Ek + Ekr. The linear kinetic energy gained by the roller and hanging mass is: Ek = ½(M + m)v2 ...
... This gravitational potential energy is changed into linear kinetic energy of the mass and of the roller plus rotational kinetic energy of the roller; Ep = Ek + Ekr. The linear kinetic energy gained by the roller and hanging mass is: Ek = ½(M + m)v2 ...
Notes
... – Also called “inertia of motion” • Momentum describes how difficult it is to bring an object to rest – The faster an object is moving, the harder it is to bring it to rest – The larger the mass of the object, the harder it is to bring it to rest – This means that momentum must depend on mass and sp ...
... – Also called “inertia of motion” • Momentum describes how difficult it is to bring an object to rest – The faster an object is moving, the harder it is to bring it to rest – The larger the mass of the object, the harder it is to bring it to rest – This means that momentum must depend on mass and sp ...
Linear acceleration of rolling objects Rotational Motion (cont.) R θ
... What is the linear acceleration of the object’s center of mass, aCM , down the incline? ...
... What is the linear acceleration of the object’s center of mass, aCM , down the incline? ...
Conservation of impulse and momentum
... is often applied when particles collide or interact. When particles impact, only impulsive forces cause a change of linear momentum. The sledgehammer applies an impulsive force to the stake. The weight of the stake is considered negligible, or non-impulsive, as compared to the force of the sledgeham ...
... is often applied when particles collide or interact. When particles impact, only impulsive forces cause a change of linear momentum. The sledgehammer applies an impulsive force to the stake. The weight of the stake is considered negligible, or non-impulsive, as compared to the force of the sledgeham ...
Solutions
... direction of the force (toward the bottom of the page) EXCEPT that since the charge in question is negative, the hand has to be turned 180 degrees which results in the right thumb pointing toward the top of the page and in the direction of the force. 35. E… Looking at the front wheel as it travels t ...
... direction of the force (toward the bottom of the page) EXCEPT that since the charge in question is negative, the hand has to be turned 180 degrees which results in the right thumb pointing toward the top of the page and in the direction of the force. 35. E… Looking at the front wheel as it travels t ...
Ch 9 Rotation
... So, rotational KE depends on I and while translational KE depends on m and v. In other words, translational KE is still ½ mv2, where v is the tangential velocity. (Translational and tangential both start with a “t.”) This is important to know for the problems later on (#’s 18 and 19). 9.3 Calculat ...
... So, rotational KE depends on I and while translational KE depends on m and v. In other words, translational KE is still ½ mv2, where v is the tangential velocity. (Translational and tangential both start with a “t.”) This is important to know for the problems later on (#’s 18 and 19). 9.3 Calculat ...