Newton`s Second Law
... Firm knowledge of vector analysis and kinematics is essential to describe the dynamics of physical systems chosen for analysis through Newton’s second law. Following problem solving strategy will allow you to tackle the problems with greater ease. Problem solving strategy: 1) Write the equation of m ...
... Firm knowledge of vector analysis and kinematics is essential to describe the dynamics of physical systems chosen for analysis through Newton’s second law. Following problem solving strategy will allow you to tackle the problems with greater ease. Problem solving strategy: 1) Write the equation of m ...
Notes for Topic 6
... distance for a. Calculate T 2 /a3 for all nine planets. What do you notice about the values of T 2 /a3 ? Explain. 7. The angular momentum vector L for motion of a particle in three dimensions is defined by L = x × p. Prove that dL/dt is equal to the torque on the particle around the origin,. 8. Redu ...
... distance for a. Calculate T 2 /a3 for all nine planets. What do you notice about the values of T 2 /a3 ? Explain. 7. The angular momentum vector L for motion of a particle in three dimensions is defined by L = x × p. Prove that dL/dt is equal to the torque on the particle around the origin,. 8. Redu ...
Parachute Jumping, Falling, and Landing
... ∆ p, given by pfinal - pinitial. After the jumper collides with the ground, he has no momentum. Therefore, pfinal = 0. Additionally, if we assume that the collision takes place along a single direction, we can use the speed on impact to determine pinitial. Momentum is given by p=mv, where m is the m ...
... ∆ p, given by pfinal - pinitial. After the jumper collides with the ground, he has no momentum. Therefore, pfinal = 0. Additionally, if we assume that the collision takes place along a single direction, we can use the speed on impact to determine pinitial. Momentum is given by p=mv, where m is the m ...
Motion in Two Dimensions
... We have seen in Chapter ?? that the momentum of a system is conserved when there are no external forces acting on the system. Conversely, an external force causes a change in momentum ∆p, with the impulse delivered by the force, F acting for a time ∆t given by: ∆p = F · ∆t The same principles that w ...
... We have seen in Chapter ?? that the momentum of a system is conserved when there are no external forces acting on the system. Conversely, an external force causes a change in momentum ∆p, with the impulse delivered by the force, F acting for a time ∆t given by: ∆p = F · ∆t The same principles that w ...
Chapter 19 Angular Momentum
... Thus if the external force in any direction is zero, then the component of the momentum of the system in that direction is a constant. For example, if there are no external forces in the x - and y -directions then ...
... Thus if the external force in any direction is zero, then the component of the momentum of the system in that direction is a constant. For example, if there are no external forces in the x - and y -directions then ...
National 4/5 Physics Dynamics and Space Summary Notes
... An object falling from a height on Earth will accelerate due to its weight. This is called free-fall. As the velocity increases, the air resistance acting on the object will increase. This means that the unbalanced force on the object will decrease, producing a smaller acceleration. Eventually, the ...
... An object falling from a height on Earth will accelerate due to its weight. This is called free-fall. As the velocity increases, the air resistance acting on the object will increase. This means that the unbalanced force on the object will decrease, producing a smaller acceleration. Eventually, the ...
Chapter 8 Rotational Dynamics continued New Seat Assignments for Thursday - www.pa.msu.edu/courses/phy231
... Reasoning Strategy 1. Select the object to which the equations for equilibrium are to be applied. 2. Draw a free-body diagram that shows all of the external forces acting on the object. 3. Choose a convenient set of x, y axes and resolve all forces into components that lie along these axes. 4. Ap ...
... Reasoning Strategy 1. Select the object to which the equations for equilibrium are to be applied. 2. Draw a free-body diagram that shows all of the external forces acting on the object. 3. Choose a convenient set of x, y axes and resolve all forces into components that lie along these axes. 4. Ap ...
Circular motion
... At any point in the motion of the object as it travels in the circle, the instantaneous velocity vector is tangent to the circle. And remember that at any point on a circle, the tangent line is perpendicular to the radius drawn to that point. So, in our diagram, the velocity vectors or perpendicular ...
... At any point in the motion of the object as it travels in the circle, the instantaneous velocity vector is tangent to the circle. And remember that at any point on a circle, the tangent line is perpendicular to the radius drawn to that point. So, in our diagram, the velocity vectors or perpendicular ...
