ANGULAR POSITION
... Example: In a microhematocrit centrifuge, small samples of blood are placed in capillary tubes. These tubes are rotated at 11,500rpm, with the bottom of the tubes 9.07cm from the axis of rotation. Find the linear speed of the bottom of the tubes. What is the centripetal acceleration at the bottom of ...
... Example: In a microhematocrit centrifuge, small samples of blood are placed in capillary tubes. These tubes are rotated at 11,500rpm, with the bottom of the tubes 9.07cm from the axis of rotation. Find the linear speed of the bottom of the tubes. What is the centripetal acceleration at the bottom of ...
A propelling neutron star in the enigmatic Be-star γ Cassiopeia
... energy into the shell at the propeller stage. Clearly, once ωm → ω∗ during the NS spin-down, the mechanical energy supply to the shell should vanish. However, even in this case the shell can be kept hot due to the gravitational energy release given by equation (2). To provide X-ray luminosity at the ...
... energy into the shell at the propeller stage. Clearly, once ωm → ω∗ during the NS spin-down, the mechanical energy supply to the shell should vanish. However, even in this case the shell can be kept hot due to the gravitational energy release given by equation (2). To provide X-ray luminosity at the ...
Phys 7221, Fall 2006: Homework # 4
... (and small) value of the energy which will allow an unstable circular orbit. Positive values of energy smaller than the local maximum allow for either bound orbits, or unbound orbits with a turning point, depending on the initial values of the system. If the angular momentum is small, and the energy ...
... (and small) value of the energy which will allow an unstable circular orbit. Positive values of energy smaller than the local maximum allow for either bound orbits, or unbound orbits with a turning point, depending on the initial values of the system. If the angular momentum is small, and the energy ...
Red 3000
... But should velocity separation be included? If so define the separation s = (v12 + v22 – 2v1v2 cos θ)½ /H0 which works well outside clusters (a little messy with F.o.G.) ...
... But should velocity separation be included? If so define the separation s = (v12 + v22 – 2v1v2 cos θ)½ /H0 which works well outside clusters (a little messy with F.o.G.) ...
Lecture14-10
... The disk will reach the bottom first – it has a smaller moment of inertia. More of its gravitational potential energy becomes translational kinetic energy, and less rotational. ...
... The disk will reach the bottom first – it has a smaller moment of inertia. More of its gravitational potential energy becomes translational kinetic energy, and less rotational. ...
11-Massive Stars
... their low collimations and fragmented morphologies, may well be the result of the complex environment, combined outflows and stellar winds, and a poor hydrodynamic collimation mechanism, such as discussed in §10.6. It has been proposed that the models with accretion disks might not be appropriate fo ...
... their low collimations and fragmented morphologies, may well be the result of the complex environment, combined outflows and stellar winds, and a poor hydrodynamic collimation mechanism, such as discussed in §10.6. It has been proposed that the models with accretion disks might not be appropriate fo ...
