10_Lecture_Outline
... change in rotational kinetic energy of the body and the power due to a torque is P = zz. • Example 10.8 shows how to calculate power from torque. ...
... change in rotational kinetic energy of the body and the power due to a torque is P = zz. • Example 10.8 shows how to calculate power from torque. ...
Wizard Test Maker
... momentum of the object? 1) 0.20 kg-m/sec due west 2) 5.0 kg-m/sec due east 3) 45 kg-m/sec due east 4) 45 kg-m/sec due west 10. A 1.0-kilogram mass changes speed from 2.0 meters per second to 5.0 meters per second. The change in the object's momentum is 1) 9.0 kg-m/sec 3) 3.0 kg-m/sec 2) 21 kg-m/sec ...
... momentum of the object? 1) 0.20 kg-m/sec due west 2) 5.0 kg-m/sec due east 3) 45 kg-m/sec due east 4) 45 kg-m/sec due west 10. A 1.0-kilogram mass changes speed from 2.0 meters per second to 5.0 meters per second. The change in the object's momentum is 1) 9.0 kg-m/sec 3) 3.0 kg-m/sec 2) 21 kg-m/sec ...
Lecture Outline - UIC Department of Physics
... change in rotational kinetic energy of the body and the power due to a torque is P = z z. • Example 10.8 shows how to calculate power from torque. ...
... change in rotational kinetic energy of the body and the power due to a torque is P = z z. • Example 10.8 shows how to calculate power from torque. ...
Newtons` second law is customarily presented to beginning students
... 1. Introduction. Center of gravity, center of mass, this concept seems very familiar. Indeed, many people including students of science have used the phrase in daily conversation. Yet, “what is the center of mass?”, and of more concern, what are its properties? We explore these ideas in the attempt ...
... 1. Introduction. Center of gravity, center of mass, this concept seems very familiar. Indeed, many people including students of science have used the phrase in daily conversation. Yet, “what is the center of mass?”, and of more concern, what are its properties? We explore these ideas in the attempt ...
Momentum and Its Conservation
... Lesson 1: The ImpulseMomentum Change Theorem • Momentum • Momentum and Impulse Connection • Real-World Applications ...
... Lesson 1: The ImpulseMomentum Change Theorem • Momentum • Momentum and Impulse Connection • Real-World Applications ...
Chapter 4. Rotation and Conservation of Angular Momentum
... The introduction of a vector notation has many benefits and simplifies the form of several relations that we will encounter. A first example is that of the infinitesimal arc vector dr that results for an infinitesimal rotation vector dθ of a rigid body (please note that we have intentionally replace ...
... The introduction of a vector notation has many benefits and simplifies the form of several relations that we will encounter. A first example is that of the infinitesimal arc vector dr that results for an infinitesimal rotation vector dθ of a rigid body (please note that we have intentionally replace ...
sy12_oct12_f11
... contact? This occurs when the normal force goes to zero or, equivalently, when all the weight is used to achieve circular motion. Fc = mg = m v2 /r v = (gr)½ (just like an object in orbit) Note this approach can also be used to estimate the maximum walking speed. Physics 207: Lecture 12, Pg 12 ...
... contact? This occurs when the normal force goes to zero or, equivalently, when all the weight is used to achieve circular motion. Fc = mg = m v2 /r v = (gr)½ (just like an object in orbit) Note this approach can also be used to estimate the maximum walking speed. Physics 207: Lecture 12, Pg 12 ...
Science 20 Unit b Final Test
... 28. If Kathryn is driving 1700 kg car at 20 m/s and she accelerates at a rate of 2.5 m/s for 4 seconds. What is the value of the impulse Kathryn’s car would experience? a. 51 000Ns b. 34 000Ns c. 17 000Ns d. 8 500 Ns e. It is impossible to tell with this amount of information ...
... 28. If Kathryn is driving 1700 kg car at 20 m/s and she accelerates at a rate of 2.5 m/s for 4 seconds. What is the value of the impulse Kathryn’s car would experience? a. 51 000Ns b. 34 000Ns c. 17 000Ns d. 8 500 Ns e. It is impossible to tell with this amount of information ...
SPH4U: Lecture 15 Today’s Agenda
... Summary: Using CM Reference Frame (m1v1,i + m2v2,i) : Determine velocity of CM VCM = ...
... Summary: Using CM Reference Frame (m1v1,i + m2v2,i) : Determine velocity of CM VCM = ...
Relativistic angular momentum
""Angular momentum tensor"" redirects to here.In physics, relativistic angular momentum refers to the mathematical formalisms and physical concepts that define angular momentum in special relativity (SR) and general relativity (GR). The relativistic quantity is subtly different from the three-dimensional quantity in classical mechanics.Angular momentum is a dynamical quantity derived from position and momentum, and is important; angular momentum is a measure of an object's ""amount of rotational motion"" and resistance to stop rotating. Also, in the same way momentum conservation corresponds to translational symmetry, angular momentum conservation corresponds to rotational symmetry – the connection between symmetries and conservation laws is made by Noether's theorem. While these concepts were originally discovered in classical mechanics – they are also true and significant in special and general relativity. In terms of abstract algebra; the invariance of angular momentum, four-momentum, and other symmetries in spacetime, are described by the Poincaré group and Lorentz group.Physical quantities which remain separate in classical physics are naturally combined in SR and GR by enforcing the postulates of relativity, an appealing characteristic. Most notably; space and time coordinates combine into the four-position, and energy and momentum combine into the four-momentum. These four-vectors depend on the frame of reference used, and change under Lorentz transformations to other inertial frames or accelerated frames.Relativistic angular momentum is less obvious. The classical definition of angular momentum is the cross product of position x with momentum p to obtain a pseudovector x×p, or alternatively as the exterior product to obtain a second order antisymmetric tensor x∧p. What does this combine with, if anything? There is another vector quantity not often discussed – it is the time-varying moment of mass (not the moment of inertia) related to the boost of the centre of mass of the system, and this combines with the classical angular momentum to form an antisymmetric tensor of second order. For rotating mass–energy distributions (such as gyroscopes, planets, stars, and black holes) instead of point-like particles, the angular momentum tensor is expressed in terms of the stress–energy tensor of the rotating object.In special relativity alone, in the rest frame of a spinning object; there is an intrinsic angular momentum analogous to the ""spin"" in quantum mechanics and relativistic quantum mechanics, although for an extended body rather than a point particle. In relativistic quantum mechanics, elementary particles have spin and this is an additional contribution to the orbital angular momentum operator, yielding the total angular momentum tensor operator. In any case, the intrinsic ""spin"" addition to the orbital angular momentum of an object can be expressed in terms of the Pauli–Lubanski pseudovector.