Lectures 2 and 3 - Goodness-of-Fit (GoF) Tests
... in [0, 1]. Therefore we conclude that, under H0 , the distribution of Dn , Cn and An does not depend on the underlying distribution F0 . In other words these statistics are distribution free under the null hypothesis, and so the computation of p-values can be easily done, as it suffices to study the ...
... in [0, 1]. Therefore we conclude that, under H0 , the distribution of Dn , Cn and An does not depend on the underlying distribution F0 . In other words these statistics are distribution free under the null hypothesis, and so the computation of p-values can be easily done, as it suffices to study the ...
Class 3 - Courses
... Hypothesis. We normally assumed that the Null hypothesis is true before hand!!!). • Level of significance of the test: 0.05 (Prob. reject H0 given it is true). • Critical value: = . = 1. 645 (This is the z score corresponding to an area to the left equal to 1-0.05=0.95) • Critical region (Rej ...
... Hypothesis. We normally assumed that the Null hypothesis is true before hand!!!). • Level of significance of the test: 0.05 (Prob. reject H0 given it is true). • Critical value: = . = 1. 645 (This is the z score corresponding to an area to the left equal to 1-0.05=0.95) • Critical region (Rej ...
1 Statistical Tests of Hypotheses
... A company is advertising that the average lifetime of their light bulbs is 1000 hours. You might question this, and want to show that in fact the lifetime is shorter. You would test H0 : µ ≥ 1000 versus Ha : µ < 1000. Rejection of H0 would then support your claim. However, nonrejection of H0 doesn’t ...
... A company is advertising that the average lifetime of their light bulbs is 1000 hours. You might question this, and want to show that in fact the lifetime is shorter. You would test H0 : µ ≥ 1000 versus Ha : µ < 1000. Rejection of H0 would then support your claim. However, nonrejection of H0 doesn’t ...
STAT 1220 Spring 2007 Common Final Exam May 3, 2007
... PART I. Consists of 30 multiple choice questions worth a total of 60 points. Read all questions carefully. You may do calculations on the test paper. Mark the number of the opscan sheet corresponding to the test question number with a Number 2 pencil or a mechanical pencil with HB lead. Mark only on ...
... PART I. Consists of 30 multiple choice questions worth a total of 60 points. Read all questions carefully. You may do calculations on the test paper. Mark the number of the opscan sheet corresponding to the test question number with a Number 2 pencil or a mechanical pencil with HB lead. Mark only on ...
Higher-order approximations for interval estimation in binomial
... length is only slightly larger than the length of Jeffreys intervals, which are credible intervals derived from Jeffreys prior. Therefore, taking the view of Brown et al. (2002), that the smooth terms are the most important in the two-term Edgeworth expansion, the r∗ confidence intervals provide rem ...
... length is only slightly larger than the length of Jeffreys intervals, which are credible intervals derived from Jeffreys prior. Therefore, taking the view of Brown et al. (2002), that the smooth terms are the most important in the two-term Edgeworth expansion, the r∗ confidence intervals provide rem ...
Descriptive Statistics
... n − 1 is used because we must acknowledge that we have estimated and do not know that true value of µ the population mean. ...
... n − 1 is used because we must acknowledge that we have estimated and do not know that true value of µ the population mean. ...
lect2m
... subsets A B together with their unions and compliments. In this combined experiment, the probabilities of the events A 2 and 1 B are such that P( A 2 ) P1 ( A), P(1 B) P2 ( B). ...
... subsets A B together with their unions and compliments. In this combined experiment, the probabilities of the events A 2 and 1 B are such that P( A 2 ) P1 ( A), P(1 B) P2 ( B). ...
