
Ego Loss May Occur 16 ELMO
... denote the circumcircles of triangles BOC and BHC, respectively. Suppose the circle with diameter AO intersects ω1 again at M , and line AM intersects ω1 again at X. Similarly, suppose the circle with diameter AH intersects ω2 again at N , and line AN intersects ω2 again at Y . Prove that lines M N ...
... denote the circumcircles of triangles BOC and BHC, respectively. Suppose the circle with diameter AO intersects ω1 again at M , and line AM intersects ω1 again at X. Similarly, suppose the circle with diameter AH intersects ω2 again at N , and line AN intersects ω2 again at Y . Prove that lines M N ...
Week 7 Stuph (and 6.1) 1. Solve: log5 (x − 2) + log 5 (2x − 9) = 2
... We want to know when we have $10, 000, or double what we started with. So we have to solve for t in the equation: 10, 000 = 5000e.055t This is the same as solving for t in the following: 2 = e.055t ln (2) = .055t ln (2) ...
... We want to know when we have $10, 000, or double what we started with. So we have to solve for t in the equation: 10, 000 = 5000e.055t This is the same as solving for t in the following: 2 = e.055t ln (2) = .055t ln (2) ...
Pigeonhole Principle - Department of Mathematics
... Let m and n be positive integers. Let aI, a2, taken from n boxes (pigeonholes), then at least two of the objects will be from the ..., ambe distinct elements of {I, 2, ..., n} samebox. This is clear enough that it does suchthat whenever at + aJ ~ n for some i,j, 1 ~ i ~ j ~ m, there exists k, 1 ~ k ...
... Let m and n be positive integers. Let aI, a2, taken from n boxes (pigeonholes), then at least two of the objects will be from the ..., ambe distinct elements of {I, 2, ..., n} samebox. This is clear enough that it does suchthat whenever at + aJ ~ n for some i,j, 1 ~ i ~ j ~ m, there exists k, 1 ~ k ...
6 8 Solving Challenging Equations
... uninterrupted pattern. For example, 5, 6, 7, 8, 9, and 10 are six consecutive whole numbers. a. ...
... uninterrupted pattern. For example, 5, 6, 7, 8, 9, and 10 are six consecutive whole numbers. a. ...
Weber problem

In geometry, the Weber problem, named after Alfred Weber, is one of the most famous problems in location theory. It requires finding a point in the plane that minimizes the sum of the transportation costs from this point to n destination points, where different destination points are associated with different costs per unit distance.The Weber problem generalizes the geometric median, which assumes transportation costs per unit distance are the same for all destination points, and the problem of computing the Fermat point, the geometric median of three points. For this reason it is sometimes called the Fermat–Weber problem, although the same name has also been used for the unweighted geometric median problem. The Weber problem is in turn generalized by the attraction–repulsion problem, which allows some of the costs to be negative, so that greater distance from some points is better.