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chap18_s05_probs
chap18_s05_probs

... = 1.7  10 kilogram per meter3  4/3    R 3 = 1.7  10-24 kilogram per meter3  13.51  (6.4  106 meters)3 = 1.7  10-24 kilogram per meter3  1.1  1021 meters3 = 0.0019 kilograms or 1.9 grams (!)  A very small mass. PROBLEM 18-10: To ionize interstellar hydrogen, a photon must have a wavelen ...
day04
day04

... Once the telescope was used to observe Venus, the geocentric theory could not explain the phases of Venus. The heliocentric theory of Copernicus explained many of Galileo’s observations, but also used circular orbits. More accurate measurements did not agree with the simple theory of Copernicus (cir ...
Student Literacy
Student Literacy

... While the stars in the constellation Orion may appear to be near each other when viewed from Earth, they are actually very far apart from one another. ...
(Diurnal) Motion of the Sky A star`s daily path is its diurnal circle
(Diurnal) Motion of the Sky A star`s daily path is its diurnal circle

Stellar Evolution and our Sun (Song “The Sun” from “Severe Tire
Stellar Evolution and our Sun (Song “The Sun” from “Severe Tire

... Velocity (bee) = distance/ time elapsed since bear stole the hive So, we can date the universe by calculating the time elapsed since any two galaxies (that are now receding) were in contact. Age = relative distance/relative velocity H0 (Hubble constant at this time) = current rate of expansion of th ...
planet
planet

... • Complicated definition - “A celestial body orbiting a star or stellar remnant that is massive enough to be rounded by its own gravity, is not massive enough to cause thermonuclear fusion, and has cleared its ...
Sample Midterm - IUPUI Physics
Sample Midterm - IUPUI Physics

... 4. We know the sun is not powered by chemical fuel (generating energy by breaking molecules) because: a) we have not yet detected any hydrocarbons in the sun b) the color of light the sun emits is not consistent with a chemical powered flame c) the sun would only last a few thousand years if it was ...
The Edge of the Solar System The Oort Cloud
The Edge of the Solar System The Oort Cloud

... sun (Kuiper belt ends at 55 AU) Centauri is 270,000 AU from sun • Proxima • Contains between 0.1 and 2 trillion comets between Oort Cloud Comets: 50-500 million • Distance km (0.33-3.33 AU) • Surface temp. in Oort Cloud ~5-6 K (Kuiper belt 30-60 K) • Named after Jan Oort ...
The Oort Cloud
The Oort Cloud

... sun (Kuiper belt ends at 55 AU) • Proxima Centauri is 270,000 AU from sun • Contains between 0.1 and 2 trillion comets • Distance between Oort Cloud Comets: 50-500 million km (0.33-3.33 AU) • Surface temp. in Oort Cloud ~5-6 K (Kuiper belt 30-60 K) • Named after Jan Oort ...
Special Relativity Worksheet
Special Relativity Worksheet

AST 301—Review for Exam 3 Consult “Guide to Reading and Study
AST 301—Review for Exam 3 Consult “Guide to Reading and Study

... that there are several techniques that could be used to detect extrasolar planets, but that basically only one has been so far successful (with a few recent detections using another technique). Can you explain why that is? (We also went over this in class.) Of the numerous extrasolar planets that ha ...
The Sun
The Sun

... The Sun The Sun is gaseous and rotates differentially, and these facts radically affect the character of solar magnetism. Because the Sun rotates more rapidly at the equator than at the poles, the differential rotation distorts the solar magnetic field, wrapping it around the solar equator, eventua ...
Parallax
Parallax

... Parallax can also be used to determine the distance to the Moon. One way to determine the lunar parallax from one location is by using a lunar eclipse. A full shadow of the Earth on the Moon has an apparent radius of curvature equal to the difference between the apparent radii of the Earth and the S ...
The Sun
The Sun

... The Sun As we look into the atmosphere at the surface of the Sun, the view becomes more and more opaque. The point where it appears to become completely opaque is called the photosphere. Thus, the photosphere may be thought of as the imaginary surface from which the solar light that we see appears ...
Gravitational Forces
Gravitational Forces

... the Earth but with a radius that is 3.5 times less than the Earth’s . ___________________________________________________________________________________ ___________________________________________________________________________________ ______________________________________________________________ ...
From last time Gravitational force Equal accelerations A fortunate
From last time Gravitational force Equal accelerations A fortunate

Calculate the Mass of the Milky Way Galaxy
Calculate the Mass of the Milky Way Galaxy

... up to 7 million light years away. By doing so he was able to come up with Hubble's Law, which said that the further galaxies were away from earth the faster they moved away from our planet. Hubble's rule proved the universe was expanding like a big balloon. In 1930, Einstein visited Wilson Observato ...
Measuring the distance to Galaxies
Measuring the distance to Galaxies

... luminous but appears only as bright as the one on the left. It must be further away The period is doubled so it is twice as luminous but its brightness is halved. It is less than twice as far away. (It will be 1.4 times as far away). ...
E3 – Stellar distances
E3 – Stellar distances

... • d = (L/(4πb))½ • d = (3.9 x 1029/(4 x π x 9.15 x 10-10))½ • d = 5.8 x 1018 m = 615 ly = 189 pc ...
NASC 1110
NASC 1110

... first minimum of the second image. ...
Earth in Space - Learning Outcomes
Earth in Space - Learning Outcomes

... A mass of 8.0 kg is moved from a point in a gravitational field where the potential is –15 J kg-1 to a point where the potential is –10 J kg-1. (a) What is the potential difference between the two points? (b) Calculate the change in potential energy of the mass. (c) How much work would have to be do ...
We see apparent retrograde motion when we pass by a
We see apparent retrograde motion when we pass by a

... The Greeks knew that the lack of observable parallax could mean one of two things: 1.  Stars are so far away that stellar parallax is too small to notice with the naked eye 2.  Earth does not orbit Sun; it is the center of the universe With rare exceptions such as Aristarchus, the Greeks rejected th ...
Solar System Formation
Solar System Formation

... Venus is one of the brightest objects in our sky, so it is clearly visible to the naked eye. It can be tricky to spot because it is always near the Sun. It rises and sets with the Sun each day. Ancient civilizations believed Venus was actually two different objects, so they called the one that rose ...
ppt
ppt

... • Is this acceleration different than g, the gravitational acceleration of an object at the Earth’s surface? – Can calculate the acceleration directly from moon’s orbital speed, and the Earth-moon distance. Physics 107, Fall 2006 ...
Solar System - eNetLearning
Solar System - eNetLearning

... Venus is one of the brightest objects in our sky, so it is clearly visible to the naked eye. It can be tricky to spot because it is always near the Sun. It rises and sets with the Sun each day. Ancient civilizations believed Venus was actually two different objects, so they called the one that rose ...
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Astronomical unit

The astronomical unit (symbol au, AU or ua) is a unit of length, roughly the distance from the Earth to the Sun. However, that distance varies as the Earth orbits the Sun, from a maximum (aphelion) to a minimum (perihelion) and back again once a year. Originally conceived as the average of Earth's aphelion and perihelion, it is now defined as exactly 7011149597870700000♠149597870700 meters (about 150 million kilometers, or 93 million miles). The astronomical unit is used primarily as a convenient yardstick for measuring distances within the Solar System or around other stars. However, it is also a fundamental component in the definition of another unit of astronomical length, the parsec.
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