ppt document
... similar tool for rotations? We already have: p = mv and SF = dp/dt. If we multiply both sides of Newton’s Second law by the radius we have (with v = r): St = r SF = r dp/dt = d(r p)/dt = dL/dt (where we have used the fact that dr/dt p = v mv = 0) ...
... similar tool for rotations? We already have: p = mv and SF = dp/dt. If we multiply both sides of Newton’s Second law by the radius we have (with v = r): St = r SF = r dp/dt = d(r p)/dt = dL/dt (where we have used the fact that dr/dt p = v mv = 0) ...
Physics 231 Topic 7: Oscillations Wade Fisher October 5-10 2012
... We can also express this in terms of an angular frequency: The angular frequency = / t = 2 π / T = the speed at which the angle is changing ...
... We can also express this in terms of an angular frequency: The angular frequency = / t = 2 π / T = the speed at which the angle is changing ...
SC81 Physics Curriculum Map 2010/2011 Revised 7/29/2010
... centripetal force and centripetal acceleration for an object in circular motion. 2. Calculate the magnitude of centripetal force and centripetal acceleration for an object in circular motion. S5 C2 PO 11 1. Predict how the force will change between two masses when the distance between them increases ...
... centripetal force and centripetal acceleration for an object in circular motion. 2. Calculate the magnitude of centripetal force and centripetal acceleration for an object in circular motion. S5 C2 PO 11 1. Predict how the force will change between two masses when the distance between them increases ...
Earthquake slip on oceanic transform faults
... (solid lines, 20 samples per second), are corrected for the instrument response and ®ltered between 1 and 150 s. The dashed lines are the synthetics. The stations are chosen to allow comparison between earthquakes on each transform and between transforms. The dates, depths and magnitudes are given. ...
... (solid lines, 20 samples per second), are corrected for the instrument response and ®ltered between 1 and 150 s. The dashed lines are the synthetics. The stations are chosen to allow comparison between earthquakes on each transform and between transforms. The dates, depths and magnitudes are given. ...
File
... 2. A car is stopped at a traffic light. If then travels along straight road so that its distance from the light is given by x(t ) bt 2 ct 3 , where b=2.40 m/s2 and c=0.120 m/s3. a) Calculate the average velocity of the car for the time interval t=0 to t=10 s. b) Calculate the instantaneous veloc ...
... 2. A car is stopped at a traffic light. If then travels along straight road so that its distance from the light is given by x(t ) bt 2 ct 3 , where b=2.40 m/s2 and c=0.120 m/s3. a) Calculate the average velocity of the car for the time interval t=0 to t=10 s. b) Calculate the instantaneous veloc ...
STP 111 THEOR - Unesco
... Cohesion is the force of attraction between molecules of the same kind e.g the molecules of water Adhesion is the force of attraction between molecules of water and glass Cohesion and adhesion explain the different action of water and mercury when spilled on a clean glass surface. Because of the adh ...
... Cohesion is the force of attraction between molecules of the same kind e.g the molecules of water Adhesion is the force of attraction between molecules of water and glass Cohesion and adhesion explain the different action of water and mercury when spilled on a clean glass surface. Because of the adh ...
Physics Experiments in Mechanics
... Physical quantities, length, mass, time, etc., are constantly being measured in the laboratory. All experimentally determined quantities contain some degree of error or uncertainty. It is important that the experimentalist knows how to record the data and results so that it’s clear just how precise ...
... Physical quantities, length, mass, time, etc., are constantly being measured in the laboratory. All experimentally determined quantities contain some degree of error or uncertainty. It is important that the experimentalist knows how to record the data and results so that it’s clear just how precise ...
PPT
... displacements. The first has a magnitude of 150 cm and makes a angle of 1200 with the positive x-axis. The resultant displacement has a magnitude of 140 cm and is directed at an angle of 35.00 to the positive x axis. Find the magnitude and direction of the second displacement. ...
... displacements. The first has a magnitude of 150 cm and makes a angle of 1200 with the positive x-axis. The resultant displacement has a magnitude of 140 cm and is directed at an angle of 35.00 to the positive x axis. Find the magnitude and direction of the second displacement. ...
Chapter 4 Notes
... • An elephant and a mouse would both have zero weight in gravity-free space. If they were moving toward you with the same speed would they bump into you with the same force? • No, the elephant is harder to stop, more inertia. ...
... • An elephant and a mouse would both have zero weight in gravity-free space. If they were moving toward you with the same speed would they bump into you with the same force? • No, the elephant is harder to stop, more inertia. ...
Chapter 5-6
... accelerated from rest to 35 m/s over a distance of 0.70 m. Find the magnitude for the average force exerted by the racket on the ball during the serve. 61.3 N [Answer] Newton’s second law: F = m a To find F, we need to find a: For constant acceleration motion: s = (vf2 – vi2 ) /(2*a) Rearrange the e ...
... accelerated from rest to 35 m/s over a distance of 0.70 m. Find the magnitude for the average force exerted by the racket on the ball during the serve. 61.3 N [Answer] Newton’s second law: F = m a To find F, we need to find a: For constant acceleration motion: s = (vf2 – vi2 ) /(2*a) Rearrange the e ...
Ball 1 of mass m moving right with speed v bounces off ball 2 with
... Answer: This one is tricky. The hoop goes faster at the top. Both hoop and puck have the same KEtrans = (1/2)mv2, but , in addition, the hoop has some KErot. In going up the hill, both hoop and puck lose the same amount of KE (KE = –mgh). But for the puck, all of its lost KE was translational KE. W ...
... Answer: This one is tricky. The hoop goes faster at the top. Both hoop and puck have the same KEtrans = (1/2)mv2, but , in addition, the hoop has some KErot. In going up the hill, both hoop and puck lose the same amount of KE (KE = –mgh). But for the puck, all of its lost KE was translational KE. W ...
SHM Part 1 - Ask Physics
... after a regular intervals of time is called periodic motion. Therefore, revolution of the Earth around the Sun is a periodic motion. The time period of this periodic motion is roughly 365 days. Therefore, T ≈ 365 days = 365 X 24 X 60 X 60 s = 31536000 s. Hence, frequency: ...
... after a regular intervals of time is called periodic motion. Therefore, revolution of the Earth around the Sun is a periodic motion. The time period of this periodic motion is roughly 365 days. Therefore, T ≈ 365 days = 365 X 24 X 60 X 60 s = 31536000 s. Hence, frequency: ...