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Work and Energy
Work and Energy

Unit P2 - Physics for your Future 2
Unit P2 - Physics for your Future 2

... 2. Bobbie is driving her 5kg toy car around. It is travelling at 10m/s when it hits the back of Heather’s (stationary) leg and sticks to it. Assuming Heather’s leg can move freely and has a mass of 10kg calculate how fast it will move after the collision. 3.3m/s ...
Newtonian Mechanics * Momentum, Energy, Collisions
Newtonian Mechanics * Momentum, Energy, Collisions

L3 ROTATIONAL MOTION
L3 ROTATIONAL MOTION

... The gravity force Fg = mg and unbalanced force is found from the acceleration of the mass FU = ma Fg = 0.18 x 9.8 = 1.764 FU = 0.18 x 1.2 = 0.216 ...
Laws - Home [www.petoskeyschools.org]
Laws - Home [www.petoskeyschools.org]

... A person is a large mass compared to a bullet. The bullet does not have enough force to overcome the inertia of the body, so there is no net force. Basically, the bullet pushes on the body and the body pushes back with that same amount of force – therefore no extra force to cause motion 19) What has ...
Chapter 5 Problems
Chapter 5 Problems

Chapter 10 Dynamics of Rotational Motion
Chapter 10 Dynamics of Rotational Motion

... If the set the zero of potential energy at the initial position of the yo-yo, then from conservation of total mechanical energy ...
exercise 10
exercise 10

Applications of Second-Order Differential Equations
Applications of Second-Order Differential Equations

Lec9
Lec9

Force and Motion I 3.0
Force and Motion I 3.0

4. Circular Motion and SHM (all higher level)
4. Circular Motion and SHM (all higher level)

... What is the main difference between them? (ii) An earthquake generates a seismic wave that takes 27 seconds to reach a recording station. If the wave travels at 5 km s−1 along the earth’s surface, how far is the station from the centre of the earthquake? (iii)Draw a diagram to show the forces acting ...
Nearly every engineering problem you will encounter will
Nearly every engineering problem you will encounter will

Lecture 1: Rotation of Rigid Body
Lecture 1: Rotation of Rigid Body

Governor - WordPress.com
Governor - WordPress.com

integrated-science-5th-edition-tillery-solution
integrated-science-5th-edition-tillery-solution

... terms of a certain mass (1 kg) and a certain acceleration (1 m/s2), the units are the same on both sides and the relationship becomes an equation, or F = ma. This is an example of an equation that defines a concept (see chapter 1). 3. A single force never occurs alone; a force is always produced by ...
Torque and rotational inertia
Torque and rotational inertia

Lab 4: Work and Energy - Instructional Physics Lab
Lab 4: Work and Energy - Instructional Physics Lab

In the previous chapter we discussed energy, and
In the previous chapter we discussed energy, and

Physics
Physics

... Using Charts and Center of Mass We have been using a chart (or matrix) to solve complex collision problems. One is replicated below for the problem outline above – m1 = 10kg, v1 = 10m/s, m2 = 15kg, v2 = 0m/s and v'1 = 2m/s. The full chart shows that v'2 = 8m/s. In the template the values at the bot ...
8-1 Newton`s Law of Universal Gravitation
8-1 Newton`s Law of Universal Gravitation

V K M I + =
V K M I + =

... A uniform rod of length L=0.5 m and mass m=1 kg is free to rotate on a frictionless pin passing through one end as in the Figure. The rod is released from rest in the horizontal position. What is (A) its angular speed when it reaches the lowest point ? (B) its initial angular acceleration ? (C) init ...
Introduction to Potential Energy Chapter 7 [ Edit ]
Introduction to Potential Energy Chapter 7 [ Edit ]

8.012 Physics I: Classical Mechanics MIT OpenCourseWare rms of Use, visit: .
8.012 Physics I: Classical Mechanics MIT OpenCourseWare rms of Use, visit: .

Further Applications of Newton`s Laws of Motion
Further Applications of Newton`s Laws of Motion

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