Binomial Distribution
... (n) Now suppose that the student has probability p of answering any one question correctly, that this probability does not change from question to question, that the questions are independent, and that there are a total of n questions. Generalize from the above result to determine the formula for th ...
... (n) Now suppose that the student has probability p of answering any one question correctly, that this probability does not change from question to question, that the questions are independent, and that there are a total of n questions. Generalize from the above result to determine the formula for th ...
Probability Distributions: Binomial & Normal
... Collect pennies with those at your table. Draw a histogram of the penny ages Describe the basic shape Do the data that you collected follow the ...
... Collect pennies with those at your table. Draw a histogram of the penny ages Describe the basic shape Do the data that you collected follow the ...
0.8 x 0.8 x 0.2 x 0.2 = 0.0256.
... Throughout the course ( in Chapters 2, 3 and 4) we have focussed on data which we can assume comes from the Normal distribution. ...
... Throughout the course ( in Chapters 2, 3 and 4) we have focussed on data which we can assume comes from the Normal distribution. ...
Full text
... Note: Since ax < w < ax + -j-, condition 4 implies that E(\n(w)) is finite. We note that the same method is used by Billingsley ([1], Ch. 1, §4) to prove a result of a similar nature involving the rate of growth of the "convergents" to a number by Diophantine ...
... Note: Since ax < w < ax + -j-, condition 4 implies that E(\n(w)) is finite. We note that the same method is used by Billingsley ([1], Ch. 1, §4) to prove a result of a similar nature involving the rate of growth of the "convergents" to a number by Diophantine ...
Original PowerPoint
... Events (continued) • The list of all possible outcomes that satisfies an event makes a set. • The events for which a roll of dice results in a pair is {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}. • The events for which a roll of dice results in a sum of 7 is {(1,6), (2,5), (3,4), (4,3), (5,2), ...
... Events (continued) • The list of all possible outcomes that satisfies an event makes a set. • The events for which a roll of dice results in a pair is {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}. • The events for which a roll of dice results in a sum of 7 is {(1,6), (2,5), (3,4), (4,3), (5,2), ...
3.3 The Addition Rule
... P(A and B) = the probability of two events A and B, in sequence. Today you will learn how to find the probability that ____ __________ _____ of two events A and B will occur. In probability and statistics, the word _____ is usually used as an “inclusive OR” rather than an “exclusive OR.” For instanc ...
... P(A and B) = the probability of two events A and B, in sequence. Today you will learn how to find the probability that ____ __________ _____ of two events A and B will occur. In probability and statistics, the word _____ is usually used as an “inclusive OR” rather than an “exclusive OR.” For instanc ...
Introduction to Probablity - Sys
... There is a 20% chance that Saskatoon will be amongst the final 5. There is a 35% chance that Moncton will be amongst the final 5 and an 8% chance that both Saskatoon and Moncton will be amongst the final 5. What is the probability that Saskatoon or Moncton will be amongst the final 5. ...
... There is a 20% chance that Saskatoon will be amongst the final 5. There is a 35% chance that Moncton will be amongst the final 5 and an 8% chance that both Saskatoon and Moncton will be amongst the final 5. What is the probability that Saskatoon or Moncton will be amongst the final 5. ...
PowerPoint Presentation - Unit 1 Module 1 Sets, elements, subsets
... Using the terminology just introduced, we have the following classical or theoretical definition of the probability of an event E. P(E) ...
... Using the terminology just introduced, we have the following classical or theoretical definition of the probability of an event E. P(E) ...