CS 70 Discrete Mathematics and Probability Theory Spring 2016
... number of edges that the resulting graph has, then it would be binomial. But unfortunately, that is not the random variable we’re looking for (Star Wars reference here). Since we are interested in the number of isolated nodes, we must instead consider a trial creating an isolated node, which happens ...
... number of edges that the resulting graph has, then it would be binomial. But unfortunately, that is not the random variable we’re looking for (Star Wars reference here). Since we are interested in the number of isolated nodes, we must instead consider a trial creating an isolated node, which happens ...
exercise 13.1 - WordPress.com
... Q.9 Mother, father and son line up at random for a family picture E: son on one end, F: father in middle Find P(E / F) If mother (M), father (F), and son (S) line up for the family picture, then the sample space will be ...
... Q.9 Mother, father and son line up at random for a family picture E: son on one end, F: father in middle Find P(E / F) If mother (M), father (F), and son (S) line up for the family picture, then the sample space will be ...
Problem Set Section 3.1 Probability Basics Indentifying Probabilities
... 4. Fruit: If there are 6 apples, 3 oranges, and 1 plum in a basket, what is the probability of choosing an apple without looking in the basket? a. Define the experiment b. Define the event c. How many outcomes are favorable to the event? d. How many total outcomes are there? e. Find the probability ...
... 4. Fruit: If there are 6 apples, 3 oranges, and 1 plum in a basket, what is the probability of choosing an apple without looking in the basket? a. Define the experiment b. Define the event c. How many outcomes are favorable to the event? d. How many total outcomes are there? e. Find the probability ...
Math/Stats 342: Solutions to Homework
... Solution: (a) What is the chance another student has the same birthday as yours? Assuming all days equally likely and none on February 29, probability is 1/365. (b) How many students so that have at least a 50% chance someone shares your birthday? Probability n people don’t share your birthday is ( ...
... Solution: (a) What is the chance another student has the same birthday as yours? Assuming all days equally likely and none on February 29, probability is 1/365. (b) How many students so that have at least a 50% chance someone shares your birthday? Probability n people don’t share your birthday is ( ...
In addition to the many formal applications of probability theory, the
... and its number is noted. This ball is then put back in the box and another ball is selected. As many balls can be selected in this way. This process is called ordered sampling with replacement. The sample space of this experiment will contain all vectors of the form (x1, . . . , xk), where xi is th ...
... and its number is noted. This ball is then put back in the box and another ball is selected. As many balls can be selected in this way. This process is called ordered sampling with replacement. The sample space of this experiment will contain all vectors of the form (x1, . . . , xk), where xi is th ...
1 Combinations, Permutations, and Elementary Probability
... A permutation of a set of n distinct symbols is an arrangement of them in a line in some order. There are n! permutations of n symbols. An r-permutation of n symbols is a permutation of r of them. There are n! (n r)! di¤erent r-permutations of n symbols. 1. Of three people (Ann, Bob and Carol) two a ...
... A permutation of a set of n distinct symbols is an arrangement of them in a line in some order. There are n! permutations of n symbols. An r-permutation of n symbols is a permutation of r of them. There are n! (n r)! di¤erent r-permutations of n symbols. 1. Of three people (Ann, Bob and Carol) two a ...
