ON POLYNOMIALS IN TWO PROJECTIONS 1. Introduction. Denote
... φj (H) = 0 for j = 1, . . . , 4. The spectral mapping theorem implies then that the polynomials φj have a common root on (0, 1), unless the summands M0 and M1 are missing in the decomposition (4.1). The latter happens if and only if the operators P1 and P2 commute, which proves the operator version ...
... φj (H) = 0 for j = 1, . . . , 4. The spectral mapping theorem implies then that the polynomials φj have a common root on (0, 1), unless the summands M0 and M1 are missing in the decomposition (4.1). The latter happens if and only if the operators P1 and P2 commute, which proves the operator version ...
$ 1 3 e A--
... More precisely, the growth (or decay) of each eigenvector in the solution is underpredicted, depending on the product h I. ...
... More precisely, the growth (or decay) of each eigenvector in the solution is underpredicted, depending on the product h I. ...
