Physics Practice Exam Solutions
... is a simple conversion from the 1-dimensional equation to circular motion. Solving for θ=(4.00)²/(2 • 0.02)= 40 rad. Now, we just make a conversion from rad to revolutions: 40 rad • [(1 rev)/(2π rad)] = 6.4 rev 16. [A] This is a conservation of energy problem, setting it up, we get: mgh+0.5mv²=0.5kx ...
... is a simple conversion from the 1-dimensional equation to circular motion. Solving for θ=(4.00)²/(2 • 0.02)= 40 rad. Now, we just make a conversion from rad to revolutions: 40 rad • [(1 rev)/(2π rad)] = 6.4 rev 16. [A] This is a conservation of energy problem, setting it up, we get: mgh+0.5mv²=0.5kx ...
ME 242 Chapter 13
... (Forces _ x) (m * g * sin mk * N ) * i m * x (Forces _ y) N - m * g * cos * j 0(static _ only) ...
... (Forces _ x) (m * g * sin mk * N ) * i m * x (Forces _ y) N - m * g * cos * j 0(static _ only) ...
IMPULSE AND MOMENTUM Impulse is the concept we use to
... states that the impulse equals the change in momentum. Very often it is not possible to determine the force acting on an object, especially if the time interval is very short. In these cases if the initial and final masses and velocities can be measured and the time of contact determined, the averag ...
... states that the impulse equals the change in momentum. Very often it is not possible to determine the force acting on an object, especially if the time interval is very short. In these cases if the initial and final masses and velocities can be measured and the time of contact determined, the averag ...
