Inverse Prime Place value Factor Multiply Divide
... Mr Brennan’s Maths Homework Vocabulary Can you define these mathematical terms we have been using this week? ...
... Mr Brennan’s Maths Homework Vocabulary Can you define these mathematical terms we have been using this week? ...
Fermat*s Little Theorem (2/24)
... Again, this says that in a mod p congruence, we can reduce exponents by p – 1. Why? If n = k(p – 1) + r, then a n = a k(p – 1) + r = (a p – 1)k a r 1k a r = a r (mod p), where the congruence is by the theorem. The proof of flt requires the following: Lemma. If GCD(a, p) =1, then the set of numbers { ...
... Again, this says that in a mod p congruence, we can reduce exponents by p – 1. Why? If n = k(p – 1) + r, then a n = a k(p – 1) + r = (a p – 1)k a r 1k a r = a r (mod p), where the congruence is by the theorem. The proof of flt requires the following: Lemma. If GCD(a, p) =1, then the set of numbers { ...
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