1st term exam solutions
... b. As the magnitude of the applied force increases, the frictional force goes from pointing down to pointing up the plane. c. As the magnitude of the applied force increases, the frictional force goes from pointing up to pointing down the plane. d. The force of static friction always equals in magni ...
... b. As the magnitude of the applied force increases, the frictional force goes from pointing down to pointing up the plane. c. As the magnitude of the applied force increases, the frictional force goes from pointing up to pointing down the plane. d. The force of static friction always equals in magni ...
Quiz __
... torque due to resistance (i.e., weight). During a bicep curl exercise, if the biceps generate 250 N of force with a moment arm of 0.05 m, what type of contraction would occur if the resistance force was ...
... torque due to resistance (i.e., weight). During a bicep curl exercise, if the biceps generate 250 N of force with a moment arm of 0.05 m, what type of contraction would occur if the resistance force was ...
Ch. 8. Energy
... 21. Define mass, weight & volume. What are their units? Refer to your textbook. 22. Would an object of mass 20 kg have greater weight on the Moon, Earth or Jupiter? Jupiter, as it has the greatest value of g. It would weigh the least on the Moon. 23. If an object weighs 400 N, what is its mass? Mass ...
... 21. Define mass, weight & volume. What are their units? Refer to your textbook. 22. Would an object of mass 20 kg have greater weight on the Moon, Earth or Jupiter? Jupiter, as it has the greatest value of g. It would weigh the least on the Moon. 23. If an object weighs 400 N, what is its mass? Mass ...
Applying Newtons Laws PPT
... Do Now: An object with mass m is moving with an initial velocity vo and speeds up to a final velocity of v in time t when an unbalanced force F is applied to it. From this information, derive Newton’s 2nd Law, F = ma ...
... Do Now: An object with mass m is moving with an initial velocity vo and speeds up to a final velocity of v in time t when an unbalanced force F is applied to it. From this information, derive Newton’s 2nd Law, F = ma ...
lecture two
... Static friction: when there is no Dynamic friction: When there is a motion. relative motion. ...
... Static friction: when there is no Dynamic friction: When there is a motion. relative motion. ...
Jeopardy - Ms. Ryan`s Weebly
... What is apply twice as much force (or reduce the mass by half)? ...
... What is apply twice as much force (or reduce the mass by half)? ...
SESSION 5
... There are 2 external forces acting on the stone. The tension in the string and the weight of the stone. As the stone swings around the direction of the weight force always points down but the direction of the tension changes. We have drawn free-body diagrams for 2 instances, when the stone is at the ...
... There are 2 external forces acting on the stone. The tension in the string and the weight of the stone. As the stone swings around the direction of the weight force always points down but the direction of the tension changes. We have drawn free-body diagrams for 2 instances, when the stone is at the ...
Motion Characteristics for Circular Motion
... • Velocity is a vector—which has both magnitude and direction – a change in either the magnitude or the direction (or both) means there is a change in velocity. ...
... • Velocity is a vector—which has both magnitude and direction – a change in either the magnitude or the direction (or both) means there is a change in velocity. ...
NEWTON`S 2nd Law of Motion
... region, one of the most forbidding territories on Earth, have an economy that revolves around the changing seasons and the animals that could be successfully hunted during these periods. Assume an that an Inuit has caught a sled full of salmon. If he pulls the sled with a force of 80 N and the sled ...
... region, one of the most forbidding territories on Earth, have an economy that revolves around the changing seasons and the animals that could be successfully hunted during these periods. Assume an that an Inuit has caught a sled full of salmon. If he pulls the sled with a force of 80 N and the sled ...
Equilibrium & Newton`s 2nd Law of Motion
... 1. A 2000-kg car’s engine exerts a westward force of 12500-N. Friction between the tires and the road is 500-N. • Sketch the free body diagram. • Calculate Fnet • Calculate the acceleration. ...
... 1. A 2000-kg car’s engine exerts a westward force of 12500-N. Friction between the tires and the road is 500-N. • Sketch the free body diagram. • Calculate Fnet • Calculate the acceleration. ...
Document
... ___________ is a stretching force and can be measured using a weighing scale. Newtons (N), like pounds, are units of ___________________________________ In the picture of the sugar and spring scale, what is tension? What force balances tension? Equilibrium Rule-when the ____ _________ acting on ...
... ___________ is a stretching force and can be measured using a weighing scale. Newtons (N), like pounds, are units of ___________________________________ In the picture of the sugar and spring scale, what is tension? What force balances tension? Equilibrium Rule-when the ____ _________ acting on ...
Forces and Motion
... to the space station with only a tool box in your possession? • We relied on Newton’s third law. The force you applied to the tool box was equal and opposite to the force that the tool box applied on you, thus it would force you to move in the opposite direction. ...
... to the space station with only a tool box in your possession? • We relied on Newton’s third law. The force you applied to the tool box was equal and opposite to the force that the tool box applied on you, thus it would force you to move in the opposite direction. ...
Centripetal Force
... A 200. g mass hung is from a 50. cm string as a conical pendulum. The period of the pendulum in a perfect circle is 1.4 s. What is the angle of the pendulum? What is the tension on the string? ...
... A 200. g mass hung is from a 50. cm string as a conical pendulum. The period of the pendulum in a perfect circle is 1.4 s. What is the angle of the pendulum? What is the tension on the string? ...
Force and motion 1
... constant velocity in a straight line unless the forces act on it to change that state. Example When you are riding a bicycle on a level path and start to free-wheel, you can keep up an almost constant velocity force some time. But eventually you will slow down, partly because of air resistance. dire ...
... constant velocity in a straight line unless the forces act on it to change that state. Example When you are riding a bicycle on a level path and start to free-wheel, you can keep up an almost constant velocity force some time. But eventually you will slow down, partly because of air resistance. dire ...
Chapter 7: Forces and Force Balances
... Coriolis force. • The higher the latitude, the stronger the Coriolis force. • The Corioils force is zero at the equator. j factor that determine weather pattern. ...
... Coriolis force. • The higher the latitude, the stronger the Coriolis force. • The Corioils force is zero at the equator. j factor that determine weather pattern. ...
Sects. 4.9 & 4.10
... • “Fictitious Forces”: If we are careful, we can the treat dynamics of particles in non-inertial frames. – Start in inertial frame, use Newton’s Laws, & make the coordinate transformation to a non-inertial frame. – Suppose, in doing this, we insist that our eqtns look like Newton’s Laws (look like t ...
... • “Fictitious Forces”: If we are careful, we can the treat dynamics of particles in non-inertial frames. – Start in inertial frame, use Newton’s Laws, & make the coordinate transformation to a non-inertial frame. – Suppose, in doing this, we insist that our eqtns look like Newton’s Laws (look like t ...
Rotational Motion and Gravity
... A 45.0-cm diameter disk rotates with a constant angular acceleration of 2.50 rad/s2. It starts from rest at t = 0, and a line drawn from the center of the disk to a point P on the rim of the disk makes an angle of 57.3° with the positive x–axis at this time. At t = 2.30 s, find (a) the angular speed ...
... A 45.0-cm diameter disk rotates with a constant angular acceleration of 2.50 rad/s2. It starts from rest at t = 0, and a line drawn from the center of the disk to a point P on the rim of the disk makes an angle of 57.3° with the positive x–axis at this time. At t = 2.30 s, find (a) the angular speed ...