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Relative Motion in Two Dimensions
Relative Motion in Two Dimensions

How Things Work
How Things Work

Acceleration
Acceleration

... The passengers ride in capsules. Each capsule moves in a circular path and accelerates. (a) ...
5. [I] How many millimeters are in 10.0 km?
5. [I] How many millimeters are in 10.0 km?

to the file
to the file

excurse to the history of weight concept: from aristotle to newton and
excurse to the history of weight concept: from aristotle to newton and

friction
friction

... Low friction (not much friction) – will keep things moving ...
Assignment 1 - UniMAP Portal
Assignment 1 - UniMAP Portal

1) An anchor is dropped in the water plummets to the ocean floor
1) An anchor is dropped in the water plummets to the ocean floor

... a) What is the KE at the start of the trial, v = 0 mph? Ans. Ko = 0 J b) What is the KE at the end of the quarter mile? Ans. Kf = ½ mv2 = 2.07x106 J c) How much work is performed on the Corvette during this trial? Ans. Wnet = K = Kf - Ko = 2.07x106 J d) What is the average net power in (W or J/s) g ...
Ph211_CH7_worksheet-f06
Ph211_CH7_worksheet-f06

... a) What is the KE at the start of the trial, v = 0 mph? Ans. Ko = 0 J b) What is the KE at the end of the quarter mile? Ans. Kf = ½ mv2 = 2.07x106 J c) How much work is performed on the Corvette during this trial? Ans. Wnet = K = Kf - Ko = 2.07x106 J d) What is the average net power in (W or J/s) g ...
Chapter 9 Rotation
Chapter 9 Rotation

Physics Fall Semester Final Answer Section
Physics Fall Semester Final Answer Section

... ____ 37. If you pull horizontally on a desk with a force of 150 N and the desk doesn't move, the friction force must be 150 N. Now if you pull with 250 N so the desk slides at constant velocity, the friction force is a. more than 150 N but less than 250 N. b. 250 N. c. more than 250. ____ 38. Suppos ...
Ch 5
Ch 5

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Student Text, pp. 203-219

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Momentum PPT

... mass of the car is 1,300 kg. A motorcycle passes the car at a speed of 30 m/sec (67 mph). The motorcycle (with rider) has a mass of 350 kg. Calculate and compare the momentum of the car and motorcycle. ...
Dynamics – Free Fall, Apparent Weight, and Friction (Honors)
Dynamics – Free Fall, Apparent Weight, and Friction (Honors)

Centripetal Acceleration
Centripetal Acceleration

... Riders in an amusement park ride shaped like a Viking ship hung from a large pivot are rotated back and forth like a rigid pendulum. Sometime near the middle of the ride, the ship is momentarily motionless at the top of its circular arc. The ship then swings down under the inuence of gravity. (a) W ...
Chapter 4 Homework Packet Inertia is the tendency
Chapter 4 Homework Packet Inertia is the tendency

Ch 6 Solutions Glencoe 2013 - Aspen High School
Ch 6 Solutions Glencoe 2013 - Aspen High School

Continuous Penalty Forces
Continuous Penalty Forces

Ffr = ma
Ffr = ma

How Safe?
How Safe?

... Linear momentum is a product of an object’s mass and velocity p  mv. Angular momentum is a product of the object’s mass, displacement from the center of rotation, and the component of velocity perpendicular to that displacement, as illustrated by Figure 9–4. If angular momentum is constant and the ...
The mechanical advantage of the magnetosphere
The mechanical advantage of the magnetosphere

... electric currents that circulate between the two regions; the associated Lorentz forces, existing in both regions as matched opposite pairs, are generally viewed as the primary mechanism by which linear momentum, derived ultimately from solar wind flow, is transferred from the magnetosphere to the i ...
Rotational Motion and Angular Momentum
Rotational Motion and Angular Momentum

Chapter 9 Rotation
Chapter 9 Rotation

... Determine the Concept From the parallel-axis theorem we know that I = I cm + Mh 2 , where Icm is the moment of inertia of the object with respect to an ...
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Newton's theorem of revolving orbits



In classical mechanics, Newton's theorem of revolving orbits identifies the type of central force needed to multiply the angular speed of a particle by a factor k without affecting its radial motion (Figures 1 and 2). Newton applied his theorem to understanding the overall rotation of orbits (apsidal precession, Figure 3) that is observed for the Moon and planets. The term ""radial motion"" signifies the motion towards or away from the center of force, whereas the angular motion is perpendicular to the radial motion.Isaac Newton derived this theorem in Propositions 43–45 of Book I of his Philosophiæ Naturalis Principia Mathematica, first published in 1687. In Proposition 43, he showed that the added force must be a central force, one whose magnitude depends only upon the distance r between the particle and a point fixed in space (the center). In Proposition 44, he derived a formula for the force, showing that it was an inverse-cube force, one that varies as the inverse cube of r. In Proposition 45 Newton extended his theorem to arbitrary central forces by assuming that the particle moved in nearly circular orbit.As noted by astrophysicist Subrahmanyan Chandrasekhar in his 1995 commentary on Newton's Principia, this theorem remained largely unknown and undeveloped for over three centuries. Since 1997, the theorem has been studied by Donald Lynden-Bell and collaborators. Its first exact extension came in 2000 with the work of Mahomed and Vawda.
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