AP Physics Chapter 2 Review
... 2. A bullet is fired through a board, 14.0 cm thick, with its line of motion perpendicular to the face of the board. If it enters with m m a speed of 450 sec and emerges with a speed of 220 sec , what is the bullet's acceleration as it passes through the board? ...
... 2. A bullet is fired through a board, 14.0 cm thick, with its line of motion perpendicular to the face of the board. If it enters with m m a speed of 450 sec and emerges with a speed of 220 sec , what is the bullet's acceleration as it passes through the board? ...
Chapter 23
... 1. The magnitude of the electric force between two protons is 2.30 10–26 N. How far apart are they? (a) 0.100 m (b) 0.022 0 m (c) 3.10 m (d) 0.005 70 m (e) 0.480 m 2. Estimate the magnitude of the electric field due to the proton in a hydrogen atom at a distance of 5.29 10–11 m, the expected pos ...
... 1. The magnitude of the electric force between two protons is 2.30 10–26 N. How far apart are they? (a) 0.100 m (b) 0.022 0 m (c) 3.10 m (d) 0.005 70 m (e) 0.480 m 2. Estimate the magnitude of the electric field due to the proton in a hydrogen atom at a distance of 5.29 10–11 m, the expected pos ...
Mechanics 4 Revision..
... Example: A ball is projected vertically upwards with a speed of 49 m s-1 from the top of a cliff, which is 180 metres above the sea. As the ball comes down it just misses the cliff. In free fall the ball would have a terminal speed of 70 m s-1 , and the air resistance is proportional to the square o ...
... Example: A ball is projected vertically upwards with a speed of 49 m s-1 from the top of a cliff, which is 180 metres above the sea. As the ball comes down it just misses the cliff. In free fall the ball would have a terminal speed of 70 m s-1 , and the air resistance is proportional to the square o ...
Friction Video Script
... wet concrete is 0.5. For rubber and a sheet of water, mew would be much, much less. The tread gives the water a place to go so that the rubber can meet the road and create some friction. Without friction, the tires would slide and the car’s inertia would keep it moving in a straight line when you mi ...
... wet concrete is 0.5. For rubber and a sheet of water, mew would be much, much less. The tread gives the water a place to go so that the rubber can meet the road and create some friction. Without friction, the tires would slide and the car’s inertia would keep it moving in a straight line when you mi ...
Assignment 1 Chapter 5: Linear Forces
... (b) Find the tension in the cable that supports the load as it is lifted at constant speed. (c) Find the tension in the cable that supports the load as it moves upward but its speed decreases by 2 m/s in each second. ANSWER (a) 11,810 N (b) 9810 N (c) T = 7810 N ...
... (b) Find the tension in the cable that supports the load as it is lifted at constant speed. (c) Find the tension in the cable that supports the load as it moves upward but its speed decreases by 2 m/s in each second. ANSWER (a) 11,810 N (b) 9810 N (c) T = 7810 N ...
Chapter 6-10 Resources
... Acceleration due to gravity on the surface of the Moon is about 1.7 m/s2, less than one fifth of the acceleration due to gravity on the surface of Earth. Thus the vertical component of projectile motion on the Moon is different from the vertical component of projectile motion on Earth. The path of a ...
... Acceleration due to gravity on the surface of the Moon is about 1.7 m/s2, less than one fifth of the acceleration due to gravity on the surface of Earth. Thus the vertical component of projectile motion on the Moon is different from the vertical component of projectile motion on Earth. The path of a ...
SUPPORT MATERIAL FOR XI CLASS PHYSICS
... Acceleration. The acceleration of an object is defined as the ratio of change of velocity of the object, and time taken i.e., Acceleration = change in velocity/time taken. Acceleration is a vector quantity. Acceleration is positive, if the velocity is increasing and is negative if velocity is decrea ...
... Acceleration. The acceleration of an object is defined as the ratio of change of velocity of the object, and time taken i.e., Acceleration = change in velocity/time taken. Acceleration is a vector quantity. Acceleration is positive, if the velocity is increasing and is negative if velocity is decrea ...
Lecture 29: Friction Examples
... Hopping into your Porsche, you floor it and accelerate at 12 m/s2 without spinning the tires. Determine the minimum coefficient of static friction between the tires and the road needed to make this possible. Sketch a free body diagram for the car. (What force causes the car’s forward acceleration?) ...
... Hopping into your Porsche, you floor it and accelerate at 12 m/s2 without spinning the tires. Determine the minimum coefficient of static friction between the tires and the road needed to make this possible. Sketch a free body diagram for the car. (What force causes the car’s forward acceleration?) ...
Chapter 23 Objective Questions The magnitude of the electric force
... A third particle with charge –Q is free to move and lies initially at rest on the perpendicular bisector of the two fixed charges a distance x from the midpoint between those charges (Fig. P23.14). (a) Show that if x is small compared with d, the motion of –Q is simple harmonic along the perpendicul ...
... A third particle with charge –Q is free to move and lies initially at rest on the perpendicular bisector of the two fixed charges a distance x from the midpoint between those charges (Fig. P23.14). (a) Show that if x is small compared with d, the motion of –Q is simple harmonic along the perpendicul ...
Final Exam
... 4. You and your friend Peter are putting new shingles on a roof pitched at 25˝ . You’re sitting on the very top of the roof when Peter, who is at the edge of the roof directly below you, 5.0 m away, asks you for the box of nails. Rather than carry the 2.5 kg box of nails down to Peter, you decide to ...
... 4. You and your friend Peter are putting new shingles on a roof pitched at 25˝ . You’re sitting on the very top of the roof when Peter, who is at the edge of the roof directly below you, 5.0 m away, asks you for the box of nails. Rather than carry the 2.5 kg box of nails down to Peter, you decide to ...
Document
... accelerates him/her to the left and the small astronaut to the right. The larger one’s velocity will be less than the smaller one’s so he/she doesn’t let go of the rope they will either collide (elastically or inelastically) and thus never make it. m ...
... accelerates him/her to the left and the small astronaut to the right. The larger one’s velocity will be less than the smaller one’s so he/she doesn’t let go of the rope they will either collide (elastically or inelastically) and thus never make it. m ...
Introduction to Modern Physics PHYX 2710
... 3. 3 Numerical problems based heavily on the material from the homework and Lab/Demo sessions (20 points each). One problem each from Chapters 2, 3 and 4. 4. You will have a formula sheet just like the one in Introduction Section 0 Lecture 1 Slide 4 the handout. 5. Test is Thursday January 29 1:30-2 ...
... 3. 3 Numerical problems based heavily on the material from the homework and Lab/Demo sessions (20 points each). One problem each from Chapters 2, 3 and 4. 4. You will have a formula sheet just like the one in Introduction Section 0 Lecture 1 Slide 4 the handout. 5. Test is Thursday January 29 1:30-2 ...
Chapter 1 notes
... due to their masses. Gravity can change the motion of an object by changing its speed, direction, or both. • All matter has mass, and gravity is a result of mass. Therefore, all matter is affected by gravity and all objects experience an attraction toward all other objects. • The mass of most object ...
... due to their masses. Gravity can change the motion of an object by changing its speed, direction, or both. • All matter has mass, and gravity is a result of mass. Therefore, all matter is affected by gravity and all objects experience an attraction toward all other objects. • The mass of most object ...
Newton's theorem of revolving orbits
In classical mechanics, Newton's theorem of revolving orbits identifies the type of central force needed to multiply the angular speed of a particle by a factor k without affecting its radial motion (Figures 1 and 2). Newton applied his theorem to understanding the overall rotation of orbits (apsidal precession, Figure 3) that is observed for the Moon and planets. The term ""radial motion"" signifies the motion towards or away from the center of force, whereas the angular motion is perpendicular to the radial motion.Isaac Newton derived this theorem in Propositions 43–45 of Book I of his Philosophiæ Naturalis Principia Mathematica, first published in 1687. In Proposition 43, he showed that the added force must be a central force, one whose magnitude depends only upon the distance r between the particle and a point fixed in space (the center). In Proposition 44, he derived a formula for the force, showing that it was an inverse-cube force, one that varies as the inverse cube of r. In Proposition 45 Newton extended his theorem to arbitrary central forces by assuming that the particle moved in nearly circular orbit.As noted by astrophysicist Subrahmanyan Chandrasekhar in his 1995 commentary on Newton's Principia, this theorem remained largely unknown and undeveloped for over three centuries. Since 1997, the theorem has been studied by Donald Lynden-Bell and collaborators. Its first exact extension came in 2000 with the work of Mahomed and Vawda.