
Lecture
... CHECKPOINT: There is a certain net flux I through a Gaussian sphere of radius r enclosing an isolated charged particle. Suppose the Gaussian surface is changed to (a) a larger Gaussian sphere, (b) a Gaussian cube with edge length equal to r, and (c) a Gaussian cube with edge length 2r. In each cas ...
... CHECKPOINT: There is a certain net flux I through a Gaussian sphere of radius r enclosing an isolated charged particle. Suppose the Gaussian surface is changed to (a) a larger Gaussian sphere, (b) a Gaussian cube with edge length equal to r, and (c) a Gaussian cube with edge length 2r. In each cas ...
Physics 7B - AB Lecture 7 May 15 Angular Momentum Model
... E) Use your right hand to show that the angular velocity points along the +z axis. ...
... E) Use your right hand to show that the angular velocity points along the +z axis. ...
Bellringer
... What do you think causes this difference? The nuts farther up on the string are being affected by gravity for a ...
... What do you think causes this difference? The nuts farther up on the string are being affected by gravity for a ...
Newton`s Law of Universal Gravitation The greatest moments in
... In this equation, “G” is a constant that would need to be discovered by experiment, “m1” and “m2” are the masses of the two objects and “r” is the distance between their centers. It doesn’t matter which mass you call “m1” and which one you call “m2”: That’s a result of Newton’s third law which state ...
... In this equation, “G” is a constant that would need to be discovered by experiment, “m1” and “m2” are the masses of the two objects and “r” is the distance between their centers. It doesn’t matter which mass you call “m1” and which one you call “m2”: That’s a result of Newton’s third law which state ...
waves
... The current (or initial) velocity: 3 m/s, vi The acceleration: 15 m/s2, a The maximum (or final) velocity: 27 m/s, vf We want to find out how much time it will take the roller coaster to accelerate from 3 m/s to 27 m/s. ...
... The current (or initial) velocity: 3 m/s, vi The acceleration: 15 m/s2, a The maximum (or final) velocity: 27 m/s, vf We want to find out how much time it will take the roller coaster to accelerate from 3 m/s to 27 m/s. ...
Axis
... In a car and not wearing a seat belt. When the car stops abruptly, you hit the dashboard. o Absence of the force of the seat belt … you followed Newton’s 1st law of motion In a car and not wearing a seat belt. Car makes a sharp left-hand corner, you slide outward (to the right). o Not due to “centri ...
... In a car and not wearing a seat belt. When the car stops abruptly, you hit the dashboard. o Absence of the force of the seat belt … you followed Newton’s 1st law of motion In a car and not wearing a seat belt. Car makes a sharp left-hand corner, you slide outward (to the right). o Not due to “centri ...
RotationalMotion - University of Colorado Boulder
... Aside: Torque, like force, is a vector quantity. Torque has a direction. Definition of vector torque : r F = cross product of r and F: "r cross F" Vector Math interlude: The cross-product of two vectors is a third vector A B C defined like this: The magnitude of A B is A B sin . The dir ...
... Aside: Torque, like force, is a vector quantity. Torque has a direction. Definition of vector torque : r F = cross product of r and F: "r cross F" Vector Math interlude: The cross-product of two vectors is a third vector A B C defined like this: The magnitude of A B is A B sin . The dir ...
Concept Questions
... cylindrical rotor . The inner radius of the washer is R. A massless string, with an object of mass m attached to the other end, is wrapped around the side of the rotor and passes over a massless pulley. Assume that there is a constant frictional torque about the axis of the rotor. The object is rele ...
... cylindrical rotor . The inner radius of the washer is R. A massless string, with an object of mass m attached to the other end, is wrapped around the side of the rotor and passes over a massless pulley. Assume that there is a constant frictional torque about the axis of the rotor. The object is rele ...
Newton's theorem of revolving orbits
In classical mechanics, Newton's theorem of revolving orbits identifies the type of central force needed to multiply the angular speed of a particle by a factor k without affecting its radial motion (Figures 1 and 2). Newton applied his theorem to understanding the overall rotation of orbits (apsidal precession, Figure 3) that is observed for the Moon and planets. The term ""radial motion"" signifies the motion towards or away from the center of force, whereas the angular motion is perpendicular to the radial motion.Isaac Newton derived this theorem in Propositions 43–45 of Book I of his Philosophiæ Naturalis Principia Mathematica, first published in 1687. In Proposition 43, he showed that the added force must be a central force, one whose magnitude depends only upon the distance r between the particle and a point fixed in space (the center). In Proposition 44, he derived a formula for the force, showing that it was an inverse-cube force, one that varies as the inverse cube of r. In Proposition 45 Newton extended his theorem to arbitrary central forces by assuming that the particle moved in nearly circular orbit.As noted by astrophysicist Subrahmanyan Chandrasekhar in his 1995 commentary on Newton's Principia, this theorem remained largely unknown and undeveloped for over three centuries. Since 1997, the theorem has been studied by Donald Lynden-Bell and collaborators. Its first exact extension came in 2000 with the work of Mahomed and Vawda.