Document
... Show me your amazing graphs 1. Get out the graphs you created 2. Check to make sure each has labeled axes, title, units, data table, trend line and YOUR NAME 3. What does this graph mean? ...
... Show me your amazing graphs 1. Get out the graphs you created 2. Check to make sure each has labeled axes, title, units, data table, trend line and YOUR NAME 3. What does this graph mean? ...
m2_FM
... - sign since force and velocity are in opposite directions For the vertical motion of an object through a fluid, the forces acting on the object are the gravitational force ...
... - sign since force and velocity are in opposite directions For the vertical motion of an object through a fluid, the forces acting on the object are the gravitational force ...
ch04_LecturePPT
... Two connected carts being accelerated by a force F applied by a string: Both carts must have the same acceleration a which is equal to the net horizontal force divided by the total mass Each cart will have a net force equal to its mass times the acceleration ...
... Two connected carts being accelerated by a force F applied by a string: Both carts must have the same acceleration a which is equal to the net horizontal force divided by the total mass Each cart will have a net force equal to its mass times the acceleration ...
Newton`s Second Law of Motion
... 1. Attach the Force Sensor to a dynamics cart so you can apply a horizontal force to the hook, directed along the sensitive axis of your particular Force Sensor. Next, attach the Accelerometer so the arrow is horizontal and parallel to the direction that the cart will roll. Orient the arrow so that ...
... 1. Attach the Force Sensor to a dynamics cart so you can apply a horizontal force to the hook, directed along the sensitive axis of your particular Force Sensor. Next, attach the Accelerometer so the arrow is horizontal and parallel to the direction that the cart will roll. Orient the arrow so that ...
Notes for Mid
... 3) A car changes its speed by 30m/s when it has an acceleration of 6m/s2. How long did this take? t = (30m/s)/(6m/s2) = 5s 1) A runner’s initial speed is 5m/s and he accelerates at 5m/s2 over a distance of 7.5 meters. What is his final speed? vf2 = (5m/s)2 + 2*(5m/s2)(7.5m) = 100m2/s2 or vf = 10m/s ...
... 3) A car changes its speed by 30m/s when it has an acceleration of 6m/s2. How long did this take? t = (30m/s)/(6m/s2) = 5s 1) A runner’s initial speed is 5m/s and he accelerates at 5m/s2 over a distance of 7.5 meters. What is his final speed? vf2 = (5m/s)2 + 2*(5m/s2)(7.5m) = 100m2/s2 or vf = 10m/s ...
Collision Prob PPT from class
... 4. Two objects having the same mass travel toward each other on a flat surface, each with a speed of 1.0 meter per second relative to the surface. The objects collide head-on and are reported to rebound after the collision, each with a speed of 2.0 meters per second relative to the surface. Which o ...
... 4. Two objects having the same mass travel toward each other on a flat surface, each with a speed of 1.0 meter per second relative to the surface. The objects collide head-on and are reported to rebound after the collision, each with a speed of 2.0 meters per second relative to the surface. Which o ...
1443-501 Spring 2002 Lecture #3
... remains at rest and an object in motion continues in motion with a constant velocity. ...
... remains at rest and an object in motion continues in motion with a constant velocity. ...
Lecture 06: Conservation of Angular Momentum
... mv v r a mr a r (ma ) r Fnet net dt February 24, 2011 ...
... mv v r a mr a r (ma ) r Fnet net dt February 24, 2011 ...
PHY–309 K. Solutions for Problem set # 10. Non
... A standing body is stable as long as its center of gravity lies above its supporting area (the actual supports and anything between them), i.e., if the vertical projection of the center of gravity down to the ground lies within the supporting area. If the center of gravity moves so that its projecti ...
... A standing body is stable as long as its center of gravity lies above its supporting area (the actual supports and anything between them), i.e., if the vertical projection of the center of gravity down to the ground lies within the supporting area. If the center of gravity moves so that its projecti ...